Ask question

Ask question

All categories

4 years ago

5

Galileo, Giotto, Magellan, Mariner 2 These are all _________________ used to travel out of Earth's orbit to explore places that

would be too dangerous for astronomers or astronauts. These devices hold instruments to collect data specific to their destinations.

1 answer:

kykrilka [37]4 years ago

5 0

Probes,and engineered unmanned space technology..

You might be interested in

NEED A PHYSICS EXPERT TO HELP ME PLS

Brut [27]

Answer:

Discharge Rate = 0.2 cubic meters per second

Explanation:

Torricelli's Law is derived from Bernoulli's equation and simply states that the speed of the efflux in a Torricelli apparatus (shown below) is directly proportional to and affected only by the height of the fluid above it.

V = √2g(10-2)

Putting value of g = 9.8 we get:

V = 12.52 m/s

Discharge rate = Q = A × V

= 1.60/100 × 12.52

= 0.2 cubic meter per second

Best Regards!

5 0

3 years ago

The magnitude of the magnetic field at point P for a certain electromagnetic wave is 2.12 μT. What is the magnitude of the elect

valkas [14]

Answer:

The electric field is $E = 636 \ V/m$

Explanation:

From the question we are told that

The magnitude of magnetic field is $B = 2.12 \mu T = 2.12*10^{-6} \ T$

The value for speed of light is $c = 3.0 *10^8 \ m/s$

Generally the magnitude of the electric field at point P is

$E = B * c$

substituting values

$E = 2.12 *10^{-6} * 3.0 *10^{8}$

$E = 636 \ V/m$

8 0

3 years ago

A double-slit experiment is set up using red light (λ = 706 nm). A first order bright fringe is seen at a given location on a sc

Elanso [62]

Answer:

λ = 470.66 nm

Explanation:

for bright fringe $y_m = \frac{m\lambda D}{d}$

D= distance between slit and screen

d= distance between the slits

for first order bright fringe m = 1,

$y_1 = \frac{1\lambda D}{d}$

$y_1 = {706*D}{d}$

for dark fringe,we have

$y_m = {(m + 1/2)\lambda D}{d}$

Now to get the dark fringes at the same location we should have;

(706)D/d = (m + 1/2)λD/d

put m = 1

(1 + 1/2)λ = (706)

λ = 470.66 nm

6 0

4 years ago

Please help me with this (with explanation)

Sergeeva-Olga [200]

Suppose the cyclist travels for a total time of <em>t</em> hours.

For 20 min = 1/3 hr, the cyclist does not move.

Over the remaining (<em>t</em> - 1/3) hr, the cyclist is moving at a constant speed of 22.0 km/hr, so that the cyclist would travel a distance of

<em>x</em> = (22.0 km/hr) • ((<em>t</em> - 1/3) hr) ≈ (22.0 km/hr) <em>t</em> - 7.33 km

If the cyclist's average speed over the total time <em>t</em> was 17.5 km/hr, then by the definition of average speed,

17.5 km/hr = <em>x</em> / <em>t</em>

Replace <em>x</em> with the distance expression from earlier:

17.5 km/hr = ((22.0 km/hr) <em>t</em> - 7.33 km) / <em>t</em>

Solve for <em>t</em> :

17.5 km/hr = 22.0 km/hr - (7.33 km) / <em>t</em>

(7.33 km) / <em>t</em> = 4.5 km/hr

<em>t</em> = (7.33 km) / (4.5 km/hr)

<em>t</em> ≈ 1.62963 hr

Then the distance the cyclist traveled must have been

<em>x</em> ≈ (22.0 km/hr) (1.62963 hr) - 7.33 km ≈ 28.5 km

and so the answer is A.

Alternatively, as soon as you arrive at

17.5 km/hr = <em>x</em> / <em>t</em>

you can instead solve for <em>t</em> in terms of <em>x</em>, then plug that into the distance equation.

<em>t</em> = <em>x</em> / (17.5 km/hr)

then

<em>x</em> ≈ (22.0 km/hr) (<em>x</em> / (17.5 km/hr)) - 7.33 km

<em>x</em> ≈ 1.25714 <em>x</em> - 7.33 km

0.25714<em>x</em> ≈ 7.33 km

<em>x</em> = (7.33 km) / 0.25714 ≈ 28.5 km

6 0

3 years ago

The results of a dart game were precise but not accurate. The accepted value of the game was the center of the dartboard. Which

hoa [83]

Answer:

The darts hit very different areas of the board.

Explanation:

8 0

3 years ago

Read 2 more answers