Answer:
True
Explanation:
The reaction between Diisopropyl ether and concentrated aqueous HI forms two initial organic products as shown in the image attached.
The hydrogen of the HI becomes attached to the oxygen in the ether leading to a cleavage of the C-O bond to yield the first compound. The I^- become attached to the other moiety in the original molecule to yield the second compound as shown in the image attached.
First thing, you convert from kPa to Pa. Then, you find the atm value of the Pa you got.
155 kPa = 155 000 Pa
1 atm = 101 325 Pa
x atm = 155 000 Pa
You divide 101 325 over 155 000 and you get about 1.53
So, 155 000 Pa = 1.53 atm.
So, T (temperature) = 25 + 273 = 298
605 kPa = 605 000 Pa
1 atm = 101 325 Pa
x atm = 605 000 Pa
You divide 605 000 over 101 325 and you get about 5.97
So 605 000 Pa = 5.97 atm
So, T = 125 + 273 = 398
P1 * V1/T1 = P2 * V2/T2
1.53 * 1/298 = 5.97 * V2/398
You calculate ad you get V2 = 0.342 L
Hope this Helps :)
Determine the number of significant figures in each of the following measurementsA). 11 soccer player
B). 0.070020 meter
C). 10,800 meters
D). 0.010 square meter
E). 5.00 cubic meters
F). 507
When it comes to equilibrium reactions, it useful to do ICE analysis. ICE stands for Initial-Change-Equilibrium. You subtract the initial and change to determine the equilibrium amounts which is the basis for Kc. Kc is the equilibrium constant of concentration which is just the ratio of products to reactant.
Let's do the ICE analysis
2 NH₃ ⇄ N₂ + 3 H₂
I 0 1.3 1.65
C +2x -x -3x
-------------------------------------
E 0.1 ? ?
The variable x is the amount of moles of the substances that reacted. You apply the stoichiometric coefficients by multiplying it by x. Now, we can solve x by:
Equilibrium NH₃ = 0.1 = 0 + 2x
x = 0.05 mol
Therefore,
Equilibrium H₂ = 1.65 - 3(0.05) = 1.5 molEquilibrium N₂ = 1..3 - 0.05 = 1.25 mol
For the second part, I am confused with the given reaction because the stoichiometric coefficients do not balance which violates the law of conservation of mass. But you should remember that the Kc values might differ because of the stoichiometric coefficient. For a reaction: aA + bB ⇄ cC, the Kc for this is
![K_{C} = \frac{[ C^{c} ]}{[ A^{a} ][ B^{b} ]}](https://tex.z-dn.net/?f=%20K_%7BC%7D%20%3D%20%5Cfrac%7B%5B%20C%5E%7Bc%7D%20%5D%7D%7B%5B%20A%5E%7Ba%7D%20%5D%5B%20B%5E%7Bb%7D%20%5D%7D%20)
Hence, Kc could vary depending on the stoichiometric coefficients of the reaction.
The colour of copper sulphate solution is blue
