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nadya68 [22]
3 years ago
7

Find the area of a cube. 5in, 5in, 5 in

Mathematics
1 answer:
Verizon [17]3 years ago
6 0

Answer:

150in²

Step-by-step explanation:

The surface area of a cube is given by the following equation where <em>s</em> is the length of a side:

A=6s^2

So, in this case, s is equal to 5:

A = 6(5)^2 = 6(25)=150in^2

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Need help please stressing out over this problem!?!?!
ludmilkaskok [199]

v =  \frac{4}{3} \times \pi \times  {r}^{3}

Finding the radius,

d = 2r, \: r =  \frac{d}{2}  =  \frac{8}{2}  = 4inches

Plugging in our values,

v =  \frac{4}{3}  \times 3.14 \times  {4}^{3}  =  \frac{4}{3}  \times 3.14 \times 64 = 267.95 {inches}^{3}  \\

Rounding to the nearest whol number,

v = 268 {inches}^{3}

6 0
3 years ago
Find the distance between the two points given
Hunter-Best [27]

Answer:

6√2

Step-by-step explanation:

from the graph the coordinates of the points are (2, 5) and (- 4, -1)

the distance is d= √(x2-x1)²+(y2-y1)² = √(-4-2)²+(-1-5)²=√72 = √2*2*2*3*3= 6√2

8 0
3 years ago
Graph and show work. Please. Helping a grandchild and I need to explain.
Usimov [2.4K]
You should try asking a tutor on the brainly app
7 0
3 years ago
A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and
Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

<h3>How to determine the equation</h3>

The equation is a secant function represented by

y =A\sec(Bt)

Where:

A represents the amplitude

So, we have:

A = 40 --- the distance of the light from each square wall

B represents the period, and it is calculated as:

B = \frac{2\pi}{T}

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

B = \frac{2\pi}{6}

Simplify

B = \frac{\pi}{3}

Substitute values for A and B in y =A\sec(Bt)

y = 40\sec(\frac{\pi}{3}t)

Rewrite as a function

d(t) = 40\sec(\frac{\pi}{3}t)

Hence, the equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0
2 years ago
winthrop Middle School had enrollment of 1,342 and a total of 215 teachers. what was the student teacher ratio for this School w
eimsori [14]
Teachers= 215
Students= 1,342

Student: Techer
= 1,342: 215
= 62.1:1
= \frac{62.1}{1}
3 0
3 years ago
Read 2 more answers
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