Answer:
2500W
Explanation:
P = W/t
As we know that
W = mgh
so:
P = mgh/t
put values
P = (200)(10)(25) / 20
<u><em>P = 2500W </em></u>
Answer:
B
the earth's mass is more than the moon
the moon's mass is less than the
Answer:
v₂ = 79.69 m/s
Explanation:
The initial diameter of the hose, d₁ = 3.0 cm = 0.03 m
Initial Cross Sectional Area, A₁ = πd₁²/4
A₁ = (π* 0.03²)/4
A₁ = 0.00071 m²
The initial speed of water from the hose, v₁ = 2.2 m/s
The diameter of the hose after blocking the end, d₂ = 0.50 cm = 0.005 m
Cross Sectional Area of the hose after blocking the end, A₂ = πd₂²/4
A₂ = (π* 0.005²)/4
A₂ = 0.0000196 m²
To get the speed, v₂, at which the water spray from the hose after blocking the end, we will use the continuity equation:
A₁v₁ = A₂v₂
0.00071 * 2.2 = 0.0000196 v₂
0.001562 = 0.0000196 v₂
v₂ = 0.001562/0.0000196
v₂ = 79.69 m/s
Answer:
Kg
Explanation:
mass is measured in kilograms
therefore its si unit is kg
Answer:
![\omega = 4.5\times 10^{-2} rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%204.5%5Ctimes%2010%5E%7B-2%7D%20rad%2Fs)
Explanation:
Given data:
Rotating cylinder length = 9 mi
diameter of cylinder is 5.9 mi
we know that linear acceleration is given as
a = r ω^2
where ω is angular velocity
so![\omega = \sqrt{\frac{a}{r}}](https://tex.z-dn.net/?f=%20%5Comega%20%3D%20%5Csqrt%7B%5Cfrac%7Ba%7D%7Br%7D%7D)
![r = \frac{5.9}[2} \frac{1609 m}{1 mi} = 4.746\times 10^{3} m](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B5.9%7D%5B2%7D%20%5Cfrac%7B1609%20m%7D%7B1%20mi%7D%20%3D%204.746%5Ctimes%2010%5E%7B3%7D%20m)
![\omega = \sqrt{\frac{9.80}{4.746\times 10^{3}}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cfrac%7B9.80%7D%7B4.746%5Ctimes%2010%5E%7B3%7D%7D%7D)
![\omega = 4.5\times 10^{-2} rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%204.5%5Ctimes%2010%5E%7B-2%7D%20rad%2Fs)