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3 years ago

What happens to the position of an object as an unbalanced force acts on?

Physics

2 answers:

jarptica [38.1K]3 years ago

5 0

Answer:

Unbalanced forces change the motion of an object. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

Lilit [14]3 years ago

4 0

ANSWER:

◼ An unbalanced force can change an object's motion.

◼ An unbalanced force acting on a still object could make the object start moving.

◼ An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.

EXAMPLE:

Ball moves from one place to another after kicking it.

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3 years ago

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3 years ago

What type of electromagnetic wave does a light bulb and a radio antenna release?

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3 years ago

A 24 cm radius aluminum ball is immersed in water. Calculate the thrust you suffer and the force. Knowing that the density of al

Illusion [34]

Answer:

W =1562.53 N

Explanation:

It is given that,

Radius of the aluminium ball, r = 24 cm = 0.24 m

The density of Aluminium, $d=2698.4\ kg/m^3$

We need to find the thrust and the force. The mass of the liquid displaced is given by :

$m=dV$

V is volume

Weight of the displaced liquid

W = mg

$W=dVg$

So,

$W=dg\times \dfrac{4}{3}\pi r^3\\\\W=2698.4\times 10\times \dfrac{4}{3}\times \pi \times (0.24)^3\\\\W=1562.53\ N$

So, the thrust and the force is 1562.53 N.

7 0

3 years ago

A 30-mm-diameter copper rod is 1 m long with a yield strength of 70 MPa. Determine the axial force necessary to cause the diamet

ivolga24 [154]

Explanation:

Given data:

d = 30 mm = 0.03 m

L = 1m

S $_{y}$ = 70 Mpa

Δd = -0.0001d

Axial force = ?

validity of elastic deformation assumption.

Solution:

O'₂ = Δd/d = (-0.0001d)/d = -0.0001

For copper,

v = 0.326 E = 119×10³ Mpa

O'₁ = O'₂/v = (-0.0001)/0.326 = 306×10⁶

∵δ = F.L/E.A and σ = F/A so,

σ = δ.E/L = O'₁ .E = (306×10⁻⁶).(119×10³) = 36.5 MPa

F = σ . A = (36.5 × 10⁻⁶) . (π/4 × (0.03)²) = 25800 KN

S $_{y}$ = 70 MPa > σ = 36.5 MPa

∵ elastic deformation assumption is valid.

so the answer is

F = 25800 K N and S $_{y}$ > σ

3 0

3 years ago