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Zolol [24]
3 years ago
7

What happens to the position of an object as an unbalanced force acts on?

Physics
2 answers:
jarptica [38.1K]3 years ago
5 0

Answer:

Unbalanced forces change the motion of an object. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

Lilit [14]3 years ago
4 0

ANSWER:

◼ An unbalanced force can change an object's motion.

◼ An unbalanced force acting on a still object could make the object start moving.

◼ An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.

EXAMPLE:

  • Ball moves from one place to another after kicking it.
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3 years ago
What is ham, I'm totally serious?
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Read 2 more answers
A highway patrol car traveling a constant speed of 105 km/h is passed by a speeding car traveling 140 km/h. Exactly 1.00 s after
vodka [1.7K]

Answer:

The elapsed time from when the speeder passes the patrol car until it is caught is 9.24 s.

Explanation:

Hi there!

The position of the patrol car at a time "t" can be calculated using this equation:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the patrol car at a time "t"

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

For the speeding car, the equation is the same only that the acceleration is zero. Then, the equation gets reduced to this:

x = x0 + v · t

Where "v" is the constant velocity.

First, let´s convert the velocity units into m/s:

140 km/h · 1000 m / 1 km · 1 h / 3600 s = 38.9 m/s

105 km/h · 1000 m / 1 km · 1 h / 3600 s = 29.2 m/s

We have to find how much time it takes the patrol car to catch the speeder after the speeder passes the patrol car.

When the patrol car catches the speeder, the position of both cars is the same:

position of the patrol car = position of the speeder

x0 + v0 · t + 1/2 · a · t² = x0 + v · t

if we place the origin of the frame of reference at the point where the patrol car starts accelerating (1 s after the speeder passes the patrol car) then, the initial position of the patrol car will be zero, while the initial position of the speeder will be the traveled distance in 1 s:

x = v · t

x = 38.9 m/s · 1 s = 38.9 m

When the patrol car accelerates, the speeder is 38.9 m ahead of it. Then:

x0 + v0 · t + 1/2 · a · t² = x0 + v · t

0 + 29.2 m/s · t + 1/2 · 3.50 m/s² · t² = 38.9 m + 38.9 m/s · t

Let´s agrupate terms and equalize to zero:

-38.9 m - 38.9 m/s · t + 29.2 m/s · t + 1.75 m/s² · t² = 0

-38.9 m - 9.70 m/s · t + 1.75 m/s² · t² = 0

Solving the quadratic equation for t using the quadratic formula:

t = 8.24 s  (the other solution is discarded because it is negative)

The elapsed time from when the speeder passes the patrol car until it is caught is (8.24 s + 1.00) 9.24 s.

3 0
3 years ago
A 2 kg toy car moves at a speed of 5 m/s.<br> What is the kinetic energy of the car?
ANTONII [103]

Answer:

<h2>The answer is 25 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

KE =  \frac{1}{2}  \times 2 \times  {5}^{2}  \\  = 1 \times  {5}^{2}

We have the final answer as

<h3>25 J</h3>

Hope this helps you

5 0
2 years ago
Multidimensional development means that:
Snezhnost [94]

Answer:

option D

Explanation:

this is because it occurs in many different dimensions, including biological, cognitive and socioemotional. this is also the answer on apex.

5 0
3 years ago
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