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3 years ago

What happens to the position of an object as an unbalanced force acts on?

Physics

2 answers:

jarptica [38.1K]3 years ago

5 0

Answer:

Unbalanced forces change the motion of an object. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

Lilit [14]3 years ago

4 0

ANSWER:

◼ An unbalanced force can change an object's motion.

◼ An unbalanced force acting on a still object could make the object start moving.

◼ An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.

EXAMPLE:

Ball moves from one place to another after kicking it.

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1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.

Lisa [10]

Answer:

(D) x = 93.8 m

Explanation:

v^2 = v0^2 + 2ax

(20 m/s)^2 = (5 m/s)^2 + 2(2 m/s^2)x

Solving for x,

x = 93.8 m

4 0

3 years ago

A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.52 radians with the

vovangra [49]

Answer:

a = 8.951 m/s²

Explanation:

given,

angle = 0.52 radians

μ_s = 0.84

μ_k = 0.48

acceleration = ?

using

F + f = m a

mg sin θ + μk mg cos θ = m a

a = g sin θ + μk g cos θ

a = 9.8 x sin 0.52 + 0.48 x 9.8 x cos 0.52

a = 4.869 + 4.082

a = 8.951 m/s²

the magnitude of acceleration is a = 8.951 m/s²

8 0

3 years ago

At launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 161 km/h; at the end

SpyIntel [72]

Answer:

$5.590278\ m/s^2$

$7.74038461538\ m/s^2$

178.888896 m

12790.56 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{161}{3.6}-0}{8}\\\Rightarrow a=5.590278\ m/s^2$

The acceleration is $5.590278\ m/s^2$

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{1610}{3.6}-\dfrac{161}{3.6}}{60-8}\\\Rightarrow a=7.74038461538\ m/s^2$

The acceleration is $7.74038461538\ m/s^2$

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 5.590278\times 8^2\\\Rightarrow s=178.888896\ m$

Distance traveled in the first 8 seconds is 178.888896 m

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=\dfrac{161}{3.6}\times 52+\dfrac{1}{2}\times 7.74038461538\times 52^2\\\Rightarrow s=12790.56\ m$

Distance traveled during 8-60 second interval is 12790.56 m

6 0

3 years ago

How much mass dose a vehicle have if it needs 29000 Newton’s of force to accelerate it at a rate of 4m/s

Olin [163]

F=ma
m=F/a
m=29000/4
m= 7250kg

4 0

2 years ago

A 4-kg hammer is lifted to a height of 10 m and dropped from rest. What was the velocity (in m/s) of the hammer when it was at a

ipn [44]

Answer:

v = 10.84 m/s

Explanation:

using the equation of motion:

v^2 = (v0)^2 + 2×a(r - r0)

<em>due to the hammer starting from rest, vo = 0 m/s and a = g , g is the gravitational acceleration.</em>

v^2 = 2×g(r - r0)

v = \sqrt{2×(-9.8)×(4 - 10)}

= 10.84 m/s

therefore, the velocity at r = 4 meters is 10.84 m/s

4 0

2 years ago