Petroleum has less density than water. So, when fire streams are applied to the burning liquid surface at such an angle that hot and / or burning oil is forced over the edge of the tank, the oil then flows down the side of the tank and you are now confronted with a fire on the ground as well as the one in the tank.
<h3>What are the reasons not to use fire streams during deal with burning oil?</h3>
When you spray water on a regular fire, you're attempting to lower the flame's temperature and contain the fire.
Fuel for an oil fire is oil. Temperature and oxidizer are present in a fire (oxygen). Due to the fact that oil is lighter than water, an explosion may result if it floats above water while water sinks beneath oil.
Consequently, water shouldn't be used to put out oil fires.
Learn more about density here:
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Answer:
T=7.4 N hence T<30 N
Explanation:
The figure is likely to be similar to the one attached. Writing the equation for forces we have
F-T=Fa/g where F is the force, T is tension, a is acceleration and g is acceleration due to gravity. Substituting the figures we have the first equation as
30 N - T = (30/9.81)a
Also, we know that T=F*a/g and substituting 10N for F we obtain the second equation as
T = (10/9.81)a
Adding the first and second equations we obtain
30 = 4.077471967
a Hence
and T=a hence
T is approximately 7.4 N
The correct answer is 432, and 720.
The thickness of a film is t= 360nm
the refractive index of oil n₀t = (m +1/2) λ
For m =0
λ = 4n₀t
= 4(1.50)(360)
= 2160nm
for m = 1
λ = 4n₀t
= 4(1.50)(360)/3
= 720nm
m = 2
λ = 4n₀t/5 = 4(1.50)(360)/5
= 432nm
The wavelength which are most strongly reflected are
432nm, 720nm.
What models are you talking about
