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Oksi-84 [34.3K]
2 years ago
5

1

Physics
1 answer:
Darya [45]2 years ago
3 0
  • Mass=0.25kg
  • Force=95N

\\ \bull\sf\dashrightarrow F=ma

\\ \bull\sf\dashrightarrow a=\dfrac{F}{m}

\\ \bull\sf\dashrightarrow a=\dfrac{95}{0.25}

\\ \bull\sf\dashrightarrow a=380m/s^2

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Answer:

r_{cm} = 0.074 m from the position of the center of the Sun

Explanation:

As we know that mass of Sun and Jupiter is given as

M_s = 1.98 \times 10^{30} kg

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distance between Sun and Jupiter is given as

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now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them

so we will have

r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}

r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}

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3 years ago
An astronomical unit (A.U.) is 1 point A) a term for defining the luminosity of a star B) the average distance from the Earth to
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7 0
2 years ago
When an automobile moves with constant speed down a highway, most of the power developed by the engine is used to compensate for
sveta [45]

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Let F is the total friction force acting on the car. The product of force and velocity is called the power developed by the engine. It is given by :

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