Answer:
Soap decreases surface tension by changing the way water behaves on the surface. Hard and soft water react differently when soap is added to them.
Explanation: i think it is this
Answer:
Because sodium and potassium are very reactive metals so they react explosively with HCL and H2SO4 evolving a large amount of heat.
Explanation:
The molarity of solution made by dissolving 15.20g of i2 in 1.33 mol of diethyl ether (CH3CH2)2O is =0.6M
calculation
molarity =moles of solute/ Kg of the solvent
mole of the solute (i2) = mass /molar mass
the molar mass of i2 = 126.9 x2 = 253.8 g/mol
moles is therefore= 15.2 g/253.8 g/mol = 0.06 moles
calculate the Kg of solvent (CH3CH2)2O
mass = moles x molar mass
molar mass of (CH3CH2)2O= 74 g/mol
mass is therefore = 1.33 moles x 74 g/mol = 98.42 grams
in Kg = 98.42 /1000 =0.09842 Kg
molarity is therefore = 0.06/0.09842 = 0.6 M
It shows the type of atoms/elements in a substance
Different types of atoms have different emission spectrum - a concept supported by Bohr quantum theory - hence one is able to identify elements in a substance using a method called spectroscopy.
Explanation:
When an electron jumps from a low energy orbital to a higher energy orbital in an atom, it absorbs a specific wavelength of electromagnetic radiation (This is called absorption spectrum). Vice versa, if the same electron jumps from a higher to a lower energy orbital it releases the equivalent quantum energy in electromagnetic wave (This is called emission spectrum). Different types of atoms of different elements have a unique spectrum identifier.
Learn More:
Learn more about spectroscopy;
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Here are the choices:
A. the output current will be much smaller than the input current.
<span>B. the output voltage will be much larger than the input voltage. </span>
<span>C. the output voltage will be much smaller than the input voltage. </span>
<span>D. the output current will be much larger than the input current
</span>
The correct answer is letter <span>B. the output voltage will be much larger than the input voltage.</span>
