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Elan Coil [88]
2 years ago
10

Which are long chains formed by the process of polymerization? subunits ethylenes monomers DNA strands

Chemistry
2 answers:
Inga [223]2 years ago
8 0

Monomers and polymers

Most large biological molecules are polymers, long chains made up of repeating molecular subunits, or building blocks, called monomers.

zhuklara [117]2 years ago
5 0

Answer:

<em>C</em>

Explanation:

simple answer

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The percent composition for nitrogen in chromium(III) nitrate is 6%.

Explanation:

6 0
3 years ago
How many milligrams are in 2.5 kg?
ludmilkaskok [199]

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There are 2500000 milligrams in 2.5 kg

7 0
2 years ago
According to the ____________________, when a physical or chemical change occurs, no atoms are created or destroyed.
solong [7]
Law of conservation of mass
7 0
3 years ago
consider a 1000-ml graduated cylinder with marks every 100 ml. a student records the volume of liquid in the cylinder as 750 ml.
Ludmilka [50]

Answer:

Explanation:

The 1000-ml graduated cylinder with marks every 100 ml has least count of 100 ml . It means it can not measure a volume less than 100 ml . It can also measure volume in the integral multiple of 100 ml like 200 ml , 300 ml , 400 ml etc perfectly .  All these have significant figure of one .

It can not measure volume like 150 , 250 , 255 , 760 etc because these measurements are not the integral multiple of 100 . 750 is not a integral multiple of 100 so it can not measure volume of 750 ml.

4 0
3 years ago
The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat
Valentin [98]

Answer:

(a)

0.0342M

(b)

t_{1/2}=17.36s\\t_{1/2}=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\

[NOBr]=\frac{1}{29.2/M}=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_{1/2}=\frac{1}{k[NOBr]_0}

Therefore, for the given initial concentrations one obtains:

t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s

Best regards.

8 0
2 years ago
Read 2 more answers
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