The nuclear fuel distribution in a nuclear reactor is chosen so that when in operation the wall temperature of the reactor is a
1 answer:
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Answer:
With this information is not possible to calculate the mass.
Explanation:
This is a characteristic problem of energy conservation, where kinetic energy becomes potential energy. For this particular problem, we have the initial speed as input data. The moment the ball comes out of the cannon we have the maximum kinetic energy, as the ball goes up the ball will gain more potential energy as the ball loses kinetic energy, until the moment the ball reaches the maximum height. At the maximum height point, the ball will have its maximum potential energy while its kinetic energy is zero. In other words, all the kinetic energy that was, in the beginning, was transformed into potential energy.
In the above equation the masses are canceled and we can determine the maximum height, by means of the initial speed.
But the mass cannot be determined, since it would be necessary to know the value of the energy, in order to determine the value of the mass.
The work done is 200 J
Explanation:
The work done by a force applied to move an object is given by:
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
In this problem, assuming that the force applied by the workers is parallel to the direction of motion of the crate, we have:
F = 10.0 N
d = 20.0 m
Therefore, the work done is:
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Answer:
Hz
Explanation:
In alternating current (AC) circuits, voltage (V) oscillates in a sine wave pattern and has a general equation as a function of time (t) as follows;
V(t) = V sin (ωt + Ф) -----------------(i)
Where;
V = amplitude value of the voltage
ω = angular frequency = 2 π f [f = cyclic frequency or simply, frequency]
Ф = phase difference between voltage and current.
<u><em>Now,</em></u>
From the question,
V(t) = 230 sin (100t) ---------------(ii)
<em><u>By comparing equations (i) and (ii) the following holds;</u></em>
V = 230
ω = 100
Ф = 0
<em><u>But;</u></em>
ω = 2 π f = 100
2 π f = 100 [divide both sides by 2]
π f = 50
f = Hz
Therefore, the frequency of the voltage is Hz