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My name is Ann [436]
3 years ago
8

The nuclear fuel distribution in a nuclear reactor is chosen so that when in operation the wall temperature of the reactor is a

constant equal to the maximum allowable temperature Ts.
Find an expression for Tt2/Ts in terms of Tt2/Ts and fL/D. For this case, plot T/Ts as a function of normalized position (x/L) and as a function of fL/D. Also, calculate and plot specific impulse divided by maximum specific impulse as a function of fL/D for a range of 0-5.
Physics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

Explanation:

We Often solve the the integral neutron transport equation using the collision probability (CP) method which usually requires flat flux (FF) approach. In this research, it has been carried out in the cylindrical nuclear fuel cell with the spatial of mesh with quadratic flux approach. This simply means that the neutron flux at any region of the nuclear fuel cell is forced to follow the pattern of a quadratic function.

Furthermore The mechanism may be referred to as the process of non-flat flux (NFF) approach. The parameters that calculated in this study are the k-eff and the distribution of neutron flux. The result shows that all parameters are in accordance with the result of SRAC.

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Your image appears 3.0 m from a plane mirror. How far IS YOUR IMAGE IN<br> RELATION TO YOU?*
Vsevolod [243]

Answer:

Being a plane mirror the Image is formed 3 metres beyond the mirror . So total distance is 3+3 = 6metres

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2 years ago
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A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5
Wittaler [7]

Answer:

8.83m

Explanation:

Given parameters:

  Acceleration  = 7.8m/s²

   Initial velocity = 0m/s

  distance covered  = 5m

Unknown:

Final velocity  = ?

Solution:

The equation to solve this problem with is given as;

    V² = U² + 2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance

 Input the parameters and solve;

    V² = 0² + 2 x 7.8 x 5 = 78

    V = √78 = 8.83m

5 0
3 years ago
A person is making homemade ice cream. She exerts a force of magnitude 28 N on the free end of the crank handle on the ice-cream
Alecsey [184]

Answer:

P = 43.2 Watt

Explanation:

As we know that the handle is moving with uniform speed

so we can find the speed as

v = \frac{2\pi R}{T}

now we have

R = 0.27 m

T = 1.1s

now we have

v = \frac{2\pi (0.27)}{1.1}

v = 1.54 m/s

now we know that power is given as

P = F.v

F = 28 N

P = 28(1.54)

P = 43.2 Watt

8 0
2 years ago
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