3 years ago

Complete the steps to factor 2x^2+6x+5x+15 by grouping

Mathematics

1 answer:

worty [1.4K]3 years ago

5 0

(2x^2 +6x) + (5x +15)
GCF for the 1st group is 2x and the 2nd is 5
2x(x +3) + 5(x +3)

(2x +5) (x+3)

You might be interested in

Math (88 points by the way)<br>I put transformation on the very first blank line by the way.

Temka [501]

This Question is actually for 44 points not 80 :(

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B-12a%5E%7B3%7Db%20%7D%7B4ab%5E%7B9%7D%20%7D" id="TexFormula1" title="\frac{-12a^{3}b

Leokris [45]

Answer:

45%-6

Step-by-step explanation:

because the question is wrong

3 0

3 years ago

Jason worked 3 hours more than Keith. Jason worked 12 hours. Which equation represents this situation, if k is the numbers of ho

ycow [4]

Answer:

j=k+3 (j=jason k+kieth)

Step-by-step explanation:

he did thrhee more so it will be adding 3 to k

8 0

3 years ago

Please HELP ASAP thank you in advanced.....will give brianlest to best answer

11Alexandr11 [23.1K]

1st option, 2nd, 4th and 5th

5 0

3 years ago

When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic

Elanso [62]

Answer:

95% Confidence interval for the mean

$142.8 \leq\mu\leq158.4$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

$cf=\sqrt{\frac{N-n}{N-1} }$

The standard deviation can be estimated as

$\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963$

The 95% confidence interval has a z value of 1.96, so it becomes:

$M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4$

5 0

3 years ago