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2 years ago

Complete the steps to factor 2x^2+6x+5x+15 by grouping

Mathematics

1 answer:

worty [1.4K]2 years ago

5 0

(2x^2 +6x) + (5x +15)
GCF for the 1st group is 2x and the 2nd is 5
2x(x +3) + 5(x +3)

(2x +5) (x+3)

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You have read 4 of the books shown. Which choice shows 2 ways of writing the fraction of these books that you read?

Olegator [25]

Total books read: 4

Total books in list: 12

So it can be shown as:

$\sf \dfrac{read \ books}{total \ books \ in \ list}$

$\hookrightarrow \sf \dfrac{4}{12}$

on simplifying

$\hookrightarrow \sf \dfrac{1}{3}$

So, option 1 is correct.

8 0

1 year ago

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Which of the following are situations that can be modeled with a quadratic function? Select all that apply.

Lina20 [59]

Answer:

Option 2 and 5 are correct.

Step-by-step explanation:

We need to tell which one of them is quadratic function.

Option 1 is exponential decay so, it is not quadratic.

Option 2 is quadratic because the diver will take the parabolic shape when jumps.

Option 3 is not quadratic.Option 4 is not quadratic it is linear.

Option 4 is again exponential not quadratic.

Option 5 is quadratic because it takes the parabolic shape again.

4 0

3 years ago

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What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

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3 years ago

Find the solution set of this inequality. Enter your answer in interval notation using grouping symbols. -2x+5<3

Andrej [43]

Answer:

( 1 , ∞ )

Step-by-step explanation:

Interval notation rounds up to infinite

8 0

2 years ago

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Between 0900 and 10 30, a man walks a distance of 27 km. What is his average speed in km/h?

kramer

Answer:

Step-by-step explanation:

0900 to1030 is 1.5 h

Take 27/1.5

Then you will get the answer

6 0

2 years ago