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WINSTONCH [101]
3 years ago
8

The range of the function f(k) = k^2 + 2k + 1 is {25, 64}. What is the function’s domain?

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
<span>k^2 + 2k + 1 = 25
</span><span>k^2 + 2k + 1 - 25 = 0
</span><span>k^2 + 2k  - 24 = 0
(k - 4)(k + 6) = 0
k - 4 = 0; k = 4
k + 6 = 0; k = -6

</span>k^2 + 2k + 1 = 64
k^2 + 2k + 1 - 64 = 0
k^2 + 2k  - 63 = 0
(k - 7)(k + 9) = 0
k - 7 = 0; k = 7
k + 9 = 0; k = -9

x = -9, -6, 4, 7

answer
<span>D. {4, 7}</span>

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Use the stem and leaf plot graph to answer the question.
kogti [31]
<h3>Answer:   13 days</h3>

====================================================

Explanation:

Count the number of leaves marked in green.

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  2. Row Two: 3 leaves (3, 6, and 9)
  3. Row Three: 5 leaves (2, 3, 4, 6, 7)
  4. Row Four: 3 leaves (1, 6, and 8)

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2 years ago
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geniusboy [140]

Answer:

C

Step-by-step explanation:

This is a stem and leaf plot. If you don't know what a stem and leaf plot is, try searching it before coming back and viewing the solution. I also see an "example" button. It might help to hit that too.

First, we sort the list of numbers. Here is what we get:

64, 66, 67, 68, 69, 74, 75, 76, 78, 79

Here, the stems are the tens digits and the leaves are the ones digits.

Therefore, for the stem 6, the leaves are:

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For the stem 7, the leaves are:

4, 5, 6, 8, 9

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3 years ago
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