Ask question

Ask question

All categories

3 years ago

7

on a map, tannersville, chadwick, and bakersville form a triangle. chadwick is 70 miles frkm tannersville and bakersvilke is 90

miles from tannersville. Which is a possible distance between chadwick and bakersville?

1 answer:

Tcecarenko [31]3 years ago

3 0

The phrasing of the question implies there are multiple choices. Is this true?

You might be interested in

A supplier sells 214 2 1 4 pounds of mulch for every 113 1 1 3 pounds of gravel. The supplier sells 172 pounds of mulch and grav

Dennis_Churaev [7]

Answer:

2.25 + 1 1/3=3.5833333 combined number of pounds of mulch and gravel sold.

2.25/3.583333 X 172=108 pounds of mulch that the supplier sells

(1 1/3) / 3.583333 X 172=64 pounds of gravel that the supplier sells.

Step-by-step explanation:

Let 'x' = pounds of gravel The ratio of mulch to gravel is given 2 1/4 / 1 1/3 Which equals 9/4 / 4/3 = 27/16

So the total gravel and much is equal to x + 27/16x = 172

Solving for 'x'

43/16 x = 172

x = 172 (16/43) = 64 pounds of gravel Mulch = 27/16x = 64 (27/16)= 108 pounds

3 0

4 years ago

Use logarithmic differentiation to find dy/dx. y = (1 + x)^1/x, x > 0

vovangra [49]

Use exp/log functions to rewrite y as

$y = (1+x)^{\frac1x} \implies y = \exp\left(\ln\left(1+x)^{\frac1x}\right)\right)$

One of the properties of logarithms lets us bring down the exponent, so

$y = \exp\left(\dfrac{\ln(1+x)}x\right)$

Now take the derivative of both sides with respect to x. By the chain and quotient rules,

$\dfrac{dy}{dx} = \exp\left(\dfrac{\ln(1+x)}x\right) \times \dfrac{\frac x{1+x} - \ln(1+x)}{x^2}$

Simplify:

$\boxed{\dfrac{dy}{dx} = \frac{x - (1+x)\ln(1+x)}{x^2(1+x)} (1+x)^{\frac1x}}$

6 0

2 years ago

15 points attached file

sdas [7]

Answer:

x = 3 renders the same output for both functions

Step-by-step explanation:

From the graph, we see that at the point x = 3 both lines intersect. This means that their y value coincide for that value of x.

We check using the functions' expressions to verify that our answer is correct. Then we evaluate both functions separately at x = 3:

$f(3)= -\frac{2}{3} (3) + 1 = -2 + 1 = -1\\g(3) = \frac{1}{3} (3) -2 = 1-2 =-1$

So we conclude that effectively, the input x=3 produces equal output value (-1) for the two given functions.

4 0

4 years ago

Read 2 more answers

Simplify the expression. − 5 + i over 2 i

I am Lyosha [343]

Answer:

-5/2

Step-by-step explanation:

5+i/2i cancel out the i's and it will be equal to 5/2

7 0

3 years ago

Solve by factoring x^2+8x+15

nadezda [96]

Factor the expression:
(x + 3) (x + 5)

3 0

3 years ago

Read 2 more answers