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2 years ago

7

on a map, tannersville, chadwick, and bakersville form a triangle. chadwick is 70 miles frkm tannersville and bakersvilke is 90

miles from tannersville. Which is a possible distance between chadwick and bakersville?

1 answer:

Tcecarenko [31]2 years ago

3 0

The phrasing of the question implies there are multiple choices. Is this true?

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Math question help pls.

devlian [24]

Answer:

i dont know the first one, but the answer to the second question is 28

Step-by-step explanation:

6 0

2 years ago

Can someone plzzz hekppp meeee

erastova [34]

Answer:

Use this formula for these kinda things.

Step-by-step explanation:

Remember The z is the hypathonous, it means the biggest side.

${a}^{2} + {b}^{2} = {c}^{2}$

where Z is going to be C

put this all together

${7}^{2} + {18}^{2} = {z}^{2}$

put it into calculator, means 373=

${z}^{2}$

therfore take the square root, it will be

$z = \sqrt{373}$

which it will be 19.31

5 0

2 years ago

= 2. Given the quadratic equation 3x2 – 8x + k = 0 has no real roots. Find the range of values of k.

VashaNatasha [74]

$\text{If there are no real roots, then}\\\\~~~~~\text{Discriminant} < 0\\\\\implies b^2 -4ac < 0\\\\\implies (-8)^2 -4 \cdot 3 k < 0\\\\\implies 64-12k < 0\\\\\ \implies 12k > 64\\\\\implies k > \dfrac{64}{12}\\\\\implies k > \dfrac{16}3\\\\\text{Interval,}~ \left( \dfrac{16}3, ~\infty\right)$

6 0

1 year ago

ROUND 977.259856871 TO 3 DECIMAL PLACES HELP!

sasho [114]

3 decimal places would be where the 9 is, since the next number is 8 , the 9 would become a 0 and the number before it (5) would become a 6

so it would be 977.260

6 0

2 years ago

Read 2 more answers

Construct 3 linear equation starting with qiven solution z = 1/3

Andreyy89

Answer:

(a) $9z+2=5$

(b) $21z-11=-4$

(c) $4z=2-2z$

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

<u>Equation 1</u>

<u /> $z=\frac{1}{3}$ <u />

Multiply both sides by 9

$9z=\frac{1}{3}\times 9\\9z=3$

Rewrite 3 as 5-2

9z=5-2

Add 2 to both sides

Our first equation is: $9z+2=5$

<u>Equation 2</u>

<u /> $z=\frac{1}{3}$ <u />

Multiply both sides by 21

$21z=\frac{1}{3}\times 21\\21z=7$

Rewrite 7 as 11-4

21z=11-4

Subtract 11 from both sides

Our second equation is: $21z-11=-4$

<u>Equation 3</u>

<u /> $z=\frac{1}{3}$ <u />

Multiply both sides by 6

$6z=\frac{1}{3}\times 6\\6z=2$

Rewrite 6z as 4z+2z

4z+2z=2

Subtract 2z from both sides

Our third equation is: $4z=2-2z$

4 0

2 years ago