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3 years ago

7

on a map, tannersville, chadwick, and bakersville form a triangle. chadwick is 70 miles frkm tannersville and bakersvilke is 90

miles from tannersville. Which is a possible distance between chadwick and bakersville?

1 answer:

Tcecarenko [31]3 years ago

3 0

The phrasing of the question implies there are multiple choices. Is this true?

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The population of a town increased from 3650 in 2012 to 4700 in 2014. Find the absolute increase.

aev [14]

Treat this like a slope formula. Y2-y1 divided by x2-x1.
Your y2 value is the second population
Y1= value of first population.
X2= second year they give
X1= first year they give.
4700-3650
_________
2014-2012

1050
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2

525 is the increase a year

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3 years ago

Write equivalent fractions for 1 2/3 and 1 7/8 using 24 as the common denominator 2 24 7 1 0

NARA [144]

<u>Answer:</u>

<u />

2×8=16

7×3=21

2/3 + 7/8 = 16/24 + 21/24

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3 years ago

Alvin has $30 and is saving $10 per week. Buzzy has $10 and he saves $15 per week. Both are saving for a guitar that costs $225

mihalych1998 [28]

It takes alvin 20 weeks, and it takes buzzy 15 weeks

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3 years ago

Read 2 more answers

Select the basic integration formula you can use to find the indefinite integral.

kondaur [170]

Answer:

$\int \dfrac{du}{u}=\log|u|+C$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$

Step-by-step explanation:

a.

$\int \dfrac{du}{u}=\log|u|+C$ $[\because \int \dfrac{dx}{x}=\log |x|+C]$

b.

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$ $[\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]$

c.

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$ $[\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]$

3 0

3 years ago

What is the value of t?

inna [77]

Answer:

4.56

Step-by-step explanation:

After this equation is simplified, it is solved the way any 1-step linear equation is solved.

__

1.4t -0.4(t -3.1) = 5.8 . . . . . . given

1.4t -0.4t +1.24 = 5.8 . . . . . eliminate parentheses

t +1.24 = 5.8 . . . . . . . . . collect terms (now you have a 1-step equation)

t = 4.56 . . . . . . . . . .subtract 1.24

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2 years ago