1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maksim [4K]
3 years ago
9

. Consider the single-engine light plane described in Prob. 2. If the specific fuel consumption is 0.42 lb of fuel per horsepowe

r per hour, the fuel capacity is 44 gal, and the maximum gross weight is 3400 lb, calculate the range and endurance at standard sea level.
Engineering
1 answer:
Trava [24]3 years ago
7 0

Answer:

Hence the Range and Endurance of single engine plane is given by

650.644 miles and 5.3528 hrs at standard sea level.

Explanation:

Given :

A single engine light plane with ,

Specific fuel consumption 0.42lb/hr/hp.

Fuel capacity =44 gal.

Gross weight =3400 lb.

To find :

Range and Endurance of the plane.

Solution:

Consider  all standard measures of standard single engine propeller plane

as

Wing span =35.8 fts.

Wing swing area=174 sq ft

parasite drag coefficient  =Cd.o.=0.025

Oswald's eff. factor= 0.8

ρ=0.002377= corresponds to standard sea level constant.

Now

Formula for Range is given by, Breguent formula.

R=(η/c)  *(Cl/Cd)*ln(W1/W0)

here η is Oswald's constant,

Now calculating lift(Cl) and drag coefficient (Cd)

Cl=W/(1/2*ρ*v^2*S)

W=Gross weight

ρ=0.002377

Assume v=200 ft/sec normally,

S=174 Sq .ft.

CI=3400/(1/2*0.002377*200*200*174)

=6800/16543.9

=0.4110

Now calculating drag constant,

AR=(wing span)^2/wing swing area

=(35.8)^2/174

=7.37

Now

Drag Coefficient

Cd=Cd.o.+ (Cl^2)/(pie*e*AR)

=0.025+(0.4110)^2/(3.142*0.8*7.36)

=0.0342

Given that 44 gal fuel capacity and in Aviation weight of fuel is 5.64 lb/gal

hence weight of fuel=W1=3400- (44*5.64)

=3151.84

Now

for specific fuel consumption=0.42  lb/hp/hr

=0.42  lb*(1/550 ft)*(1/3600)sec

=2.12 *10^-7 lb/ft/sec

Now further calculating range

R=(η/c)  *(Cl/Cd)*ln(W1/W0)

={0.8/(2.12*10^-7)}*(0.4110/0.0342)*ln(3151.84/3400)

=0.024908/0.072504

=0.34354*10^7

=3.4353 *10^6 fts.

1mi =5280 ft

=(3.4353/5280)*10^6

=650.644 miles

Now

For Endurance

E=(η/c)*{(Cl^3/2)/Cd}*(2*ρ*S)^1/2*[1/(W1)^1/2  -1/(W0)^1/2].

=(0.8/2.12*10^-7)*{(0.4110^3/2)/0.0342}*(2*0.002377*174)^1/2*[1/(3151.84)^1/2  -1/(3400)^1/2]

=3.7735*10^6*7.7043*0.8272*0.0006629

=0.01927*10^6

=1.927*10^4 sec

here 1hr =3600 sec

E=(1.927/3600)*10^4

=5.3528 hrs

You might be interested in
Match the scenario to the term it represents.
Ann [662]

Answer:

i nrfvewv

Explanation:

3 0
3 years ago
What type of car engine is best for cold weather.
Komok [63]

Answer:Antifreeze/coolant

Explanation: keeps your engine cool in warm weather and keeps it from freezing up in the winter. A 50-50 mix of full strength coolant and water generally protects to around -30 degrees Fahrenheit. Make sure you check with the supplier or your owner's manual for the correct formulation

5 0
2 years ago
If a car sits out in the sun every day for a long time can light from the sun damage the car paint
Reika [66]

Answer:

i think yes it could make the color go lighter

Explanation:

6 0
3 years ago
Read 2 more answers
The acceleration due to gravity on the surface of the moon is 1.62m/s^2. The moon's radius is Rm+1738km. A) What is the weight i
Anastaziya [24]

Answer:

weight is 12.6 N

force is 4.05 N

Explanation:

given data

acceleration = 1.62 m/s²

radius = 1738 km

mass = 10 kg

distance = 1738 km

to find out

weight and force

solution

we apply here weight formula that is

weight =  mass × acceleration    ...................1

put here value

weight =  10 × 1.26

weight = 12.6 N

and

force = mass × An

force = 10 × 1.62 (1738/ 1738+1738)² = 4.05 N

so force is 4.05 N

4 0
3 years ago
The function below takes two numeric parameters. The first parameter specifies the number of hours a person worked and the secon
Mekhanik [1.2K]

def calculate_pay(total_worked_hours, rate_per_hour):

  if total_hours_worked > 40:

 # anything over 40 hours earns the overtime rate

 overtimeRate = 2 * rate _per_hour

  return (40 * rate_per_hour) + ((total_worked_hours - 40) * overtimeRate

  else:

  # if you didn't work over 40 hours, there is no overtime

   overtime = 0

   return total_worked_hours * rate_per_hour

Explanation:

  • First we create the calculate_pay function which will takes 2 parameters.
  • Secondly ,inside the function we check if  the total_worked_hours is greater than 40 and then return the pay by calculating with the help of formula for work over 40 hours.
  • If the total work hour is less than 40 then we  return the pay by multiplying the total_worked_hours with rate_per_hour.

5 0
3 years ago
Other questions:
  • The flowchart below shows the design steps required to build a working model.
    6·1 answer
  • The flatbed truck carries a large section of circular pipe secured only by the two fixed blocks A and B of height h. The truck i
    14·2 answers
  • Number the statements listed below in the order that they would occur in engine operation. Then, label these stages as intake, c
    14·1 answer
  • If a ball is dropped from a height its velocity will increase until it hits the ground, assuming that aerodynamic drag due to th
    6·1 answer
  • At what stage of development is an engineering team the most productive?
    6·2 answers
  • How may a Professional Engineer provide notice of licensure to clients?
    9·1 answer
  • What are the major types of stone used in construction? How do their properties differ? What sequence of operations would be use
    10·1 answer
  • Would you ever date a transgender person??
    8·2 answers
  • How buy airpods in my phone​
    7·2 answers
  • A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 15 trays and
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!