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Elena L [17]
3 years ago
5

How can you do this 5.2.4: Rating?

Engineering
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0

Answer:

whats the question

Explanation:

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Are connected to a larger parent organization that can help with marketing and provide will have the same
Setler [38]
Answer: D. Franchises

7 0
3 years ago
HW6P2 (20 points) The recorded daily temperature (°F) in New York City and in Denver, Colorado during the month of January 2014
Maurinko [17]

Answer & Explanation:

function Temprature

NYC=[33 33 18 29 40 55 19 22 32 37 58 54 51 52 45 41 45 39 36 45 33 18 19 19 28 34 44 21 23 30 39];

DEN=[39 48 61 39 14 37 43 38 46 39 55 46 46 39 54 45 52 52 62 45 62 40 25 57 60 57 20 32 50 48 28];

%AVERAGE CALCULATION AND ROUND TO NEAREST INT

avgNYC=round(mean(NYC));

avgDEN=round(mean(DEN));

fprintf('\nThe average temperature for the month of January in New York city is %g (F)',avgNYC);

fprintf('\nThe average temperature for the month of January in Denvar is %g (F)',avgDEN);

%part B

count=1;

NNYC=0;

NDEN=0;

while count<=length(NYC)

   if NYC(count)>avgNYC

       NNYC=NNYC+1;

   end

   if DEN(count)>avgDEN

        NDEN=NDEN+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in New York city was above the average',NNYC);

fprintf('\nDuring %g days, the temprature in Denvar was above the average',NDEN);

%part C

count=1;

highDen=0;

while count<=length(NYC)

   if NYC(count)>DEN(count)

       highDen=highDen+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in Denver was higher than the temprature in New York city.\n',highDen);

end

%output

check the attachment for additional Information

8 0
4 years ago
Which test element is used to apply test execution settings for the main business flow excluding Login and Log out 1) Run time c
Svet_ta [14]

Test element is used to apply test execution settings for the main business flow excluding Login and Log out is "Transaction  controller"

<u>Explanation:</u>

Transaction controllers are a technoscientifically kind of controllers that produce an additional sample that measures the overall time is taken or response time to perform its nested samplers.

The Controller has two checkboxes,those are

1.Generate Parent Samples

2. Include term of the timer and pre-post processors in the produced sample - It is the time which involves all processing samples within the Transaction controller, not just the HTTP samples. In Case one sample is lost or crashed then the entire Transaction Controller will fail. In case anyone sample assertion is failed then the complete Transaction Controller will fail.

3 0
4 years ago
10POINTS
deff fn [24]

Answer:

Chinese

Explanation:

I hope this helps

3 0
3 years ago
Steam enters a turbine operating at steady state at 2 MPa, 323 °C with a velocity of 65 m/s. Saturated vapor exits at 0.1 MPa an
Lera25 [3.4K]

Answer:

\dot Q_{out} = 13369.104\,kW

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

-\dot Q_{out} - \dot W_{out} + \dot H_{in} - \dot H_{out} + \dot K_{in} - \dot K_{out} + \dot U_{in} - \dot U_{out} = 0

The rate of heat transfer between the turbine and its surroundings is:

\dot Q_{out} = \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out} - \dot W_{out} + \dot U_{in} - \dot U_{out}

The specific enthalpies at inlet and outlet are, respectively:

h_{in} = 3076.41\,\frac{kJ}{kg}

h_{out} = 2675.0\,\frac{kJ}{kg}

The required output is:

\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW\dot Q_{out} = 13369.104\,kW

4 0
3 years ago
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