Answer:
Pharming
Phishing
Explanation:
Pharming is used equal like Phishing, because using fake websites, but in this case, is not necessary spam in your email.
Phishing is used like spam, and they pretend to be real companies by email, if you click in the email you will go a supposedly a real website, you put your information like passwords in these websites
You can prevent these techniques using antivirus and you can verify the websites because fake websites don't have the https:// protocol.
A business can prevent this issue using corporatize email and configuring the company network with security protocols and encrypt the information.
What element is the primary constituent of ferrous alloys?
Answer: Ferrous alloys or metals are metals that consist mostly of iron (Fe). Steel is an iron-based alloy containing typically less than 1% carbon, where iron frequently contains 2% or more carbon.
Answer:
The power absorbed by the 60 ohm resistor is 1.064 W
Explanation:
When there's no load connected to the source (open circuit) its voltage output is ideal, since there won't be any voltage drop across it's internal resistance. When there's a shor circuit, the only load is the internal resistance of the source, so we can use Ohm's law to compute the internal resistance, as shown bellow:
Rinternal = Vopenload/Ishortcircuit
Rinternal = 8/200 = 0.04 Ohm
When we connect a load to this source, the total load we'll be the external resistance plus the internal resistance. We can now compute the curent flow when there's a 60 Ohm resistance connected to the terminals of the source by using Ohm's law again:
I = Vsource/(Rexternal + Rinternal)
I = 8/(60 + 0.04) = 8/(60.04) = 0.1332 A
The absorbed power is the product of the voltage across the terminals of the resistor and the current that goes through it. The current is the one we calculated above and the voltage across it's terminals is given by I*R, so the power output is:
P = I*Vresistor
P = I*(I*R)
P = R*I^2 = 60*(0.1332)^2 = 1.064 W
The amount of settlement that would occur at the end of 1.5 year and 5 year are 7.3 cm and 13.14 cm respectively.
<h3>How to determine the amount of settlement?</h3>
For a layer of 3.8 m thickness, we were given the following parameters:
U = 50% = 0.5.
Sc = 7.3 cm.
For Sf, we have:
Sf = Sc/U
Sf = 7.3/0.5
Sf = 14.6
Therefore, Sf for a layer of 38 m thickness is given by:
Sf = 14.6 × 38/3.8
Sf = 146 cm.
At 50%, the time for a layer of 3.8 m thickness is: = 1.5 year.
At 50%, the time for a layer of 38 m thickness is:
= 1.5 × (38/3.8)²
= 150 years.
For the thickness of 38 m, U₂ is given by:
The new settlement after 1.5 year is:
Sc = U₂Sf
Sc = 0.05 × 146
Sc = 7.3 cm.
For time, t₂ = 5 year:
The new settlement after 5 year is:
Sc = U₂Sf
Sc = 0.09 × 146
Sc = 13.14 cm.
Read more on clay layer here: brainly.com/question/22238205