. A constant current of 1 ampere is measured flowing into the positive reference terminal of a pair of leads whose voltage we’ll
call vp. Calculate the absorbed power at t = 1 s if vp(t) equals (a) +1 V; (b) −1 V; (c) 2 + 5 cos(5t) V; (d) 4e−2t V, (e) Explain the significance of a negative value for absorbed power
1 answer:
Answer:
(a) 1W
(b) -1W
(c) 6.98W
(d) 0.541W
(e)Negative value of absorbed
power indicates that the object is
actually supplying power to some
other object. That is negative
absorbed power is equal to
positive supplied power.
Explanation:
Detailed explanation of all the parts of the question are given in attached files.
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Answer:
1) A=282.6 mm
2)
3)T=0.42 sec
4)f= 2.24 Hz
Explanation:
Given that
V=3.5 m/s at x=150 mm ------------1
V=2.5 m/s at x=225 mm ------------2
Where x measured from mid position.
We know that velocity in simple harmonic given as
Where A is the amplitude and ω is the natural frequency of simple harmonic motion.
From equation 1 and 2
------3
--------4
Now by dividing equation 3 by 4
So A=0.2826 m
A=282.6 mm
Now by putting the values of A in the equation 3
ω=14.609 rad/s
Frequency
ω= 2πf
14.609= 2 x π x f
f= 2.24 Hz
Maximum acceleration
Time period T
T=0.42 sec