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natka813 [3]
3 years ago
5

A designer needs to select the material for a plate under tensile stress. Assuming that the applied tensile force is 13,000 lb a

nd the area under the stress is 4 square inches, determine which material should be selected to assure safety. Assume safety factor is 2. Material A: Ultimate Tensile stress is 8000 lb/in2Material B: Ultimate Tensile stress is 5500 lb/in2
Engineering
1 answer:
natulia [17]3 years ago
4 0
Wow Muy bien no se que dice pero bien.
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What is the name of the type of rocker arm stud that does not require a valve adjustment?
-Dominant- [34]

Answer:

Jesel Premium Stud rockers

Explanation:

This specific stud rocker does not need a valve adjustment. It does not need stud girdles or pushed guide plates. It can be adjusted on a steel stanchion post.

(have a good day and I hope that this explanation fits what you needed to know!)

4 0
3 years ago
A cylindrical metal specimen having an original diameter of 10.55 mm and gauge length of 54.5 mm is pulled in tension until frac
kumpel [21]

Answer:

(a) 53.94%

(b) 26.61%

Explanation:

Change in area will be given by

\triangle A=\frac {\pi(R_o^{2}-r_n^{2})}{\pi R_o^{2}} where \triangle A represent change in area R is radius and subscripts O and n represent original and new respectively.

Substituting 10.55/2 for original radius and 7.16/2 for new radius then

\triangle A=\frac {\pi(5.275^{2}-3.58^{2})}{\pi 5.275^{2}}\times 100\approx 53.94

(b)

Similarly, percentage elongation will be found by dividing the change in length by the the original length. In this case, rhe original length was 54.5mm and goes to 69 mm so the change in length is given by subtracting the final length from the original length

Percentage elongation is \frac {69-54.5}{54.5}\times 100\approx 26.61

6 0
4 years ago
1. Saturated steam at 4 bars absolute pressure with a mean velocity of 3 m/s flows through a horizontal SS304 stainless-steel pi
saveliy_v [14]

Answer:

(a) Rate of heat transfer = 34.65 W/m

(b) quality of outlet of pipe  x = 0.967

(c) Temperature of outer surface of insulation, T₂ = U1.157°C

Yes it is safe to touch, (But gentle touch)

Explanation:

Detailed explanation is given in the attach document.

5 0
4 years ago
How much power is needed to operate a Carnot heat pump if the pump receives heat 10°C and delivers 50 kW of heat at 40°C? at A)
mariarad [96]

Answer:

Power needed to pump=4.79 KW.

Explanation:

Given that:T_{1}=283K,T_{2}=313K,Q_{H}=50KW

We know that coefficient of performance of heat pump

 COP=\dfrac{T_{H}}{T_{H}-T_{L}}

So COP=\dfrac{313}{313-283}

      COP=10.43

COP=\frac{Q_{H}}{W_{in}}

      10.43 =\frac{50}{W_{in}}

W_{in}=4.79 KW

So power needed to pump=4.79 KW.

3 0
3 years ago
When a man returns to his well-sealed house on a summer day, he finds that the house is at 35°C. He turns on the air conditioner
ipn [44]

Answer:

\dot W = 1.667\, kW

Explanation:

A well-sealed house means that there is no mass interaction between air indoors and outdoors. Hence, cooling process is isochoric. The heat removed by the air conditioner is:

\dot Q_{L} = \frac{m_{air}}{\Delta t} \cdot c_{v, air} \cdot (T_{o}-T_{f})\\\dot Q_{L} = \frac{800\, kg}{(30\, min)\cdot (\frac{60\, s}{1 \, min} )}\cdot (0.7 \frac{kJ}{kg \cdot K}) \cdot (15\, K)\\\dot Q_{L} = 4.667\, kW

The power drawn by the air conditioner is:

\dot W = \frac{\dot Q_{L}}{COP_{R}} \\\dot W = \frac {4.667\, kW}{2.8}\\\dot W = 1.667\, kW

3 0
3 years ago
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