Answer:
1. All engines exhibit wear over time ⇒ <em>Synthetic Improves engine protection by resisting oil breakdown.</em>
Synthetic oil does not breakdown so easily which means that it protects the engine more and protects it from wearing.
2. Engines are cold at start-up and not while running ⇒ <em> Synthetic provides maximum protection in extreme hot and cold temperature conditions.</em>
By providing protection for the engine during cold and hot conditions, the engine will not be too cold when the car is started up.
3. If oil is thicker, engines lose power and efficiency ⇒ <em>Synthetic has greater resistance to oil thickening to maintain engine efficiency.</em>
Part of the characteristics of synthetic oil is that it does not get as thick as regular oil which means that the adverse effects of thick oil are spared on the engine.
365gpa I don’t even know what it is but this is with 10 point and I need it
Answer:
Rotary engine was early known by the name of internal combustion engine. It convert heat from a high pressure of combustion. The main advantage of rotary engine is that it can be operate with less number of vibration. It works on the principle of converting pressure into rotating motion. In rotary engine the expansion pressure is applied on the flank rotor.
Answer:
Explanation:
Before: PT= 0.10, PB= 0.03 (given) ET = 2.5 ER = 2.0 (Table 6.5)
fHV= 0.847 (Eq. 6.5) PHF = 0.95, fp= 0.90, N=2, V = 2200 (given)
vp= V/[PHF⋅fHVTB⋅fp⋅N] = 1518.9 (Eq. 6.3)
BFFS = 50+5, BFFS =55 (given) fLW= 6.6
TLC=6+3=9 fLC= 0.65
fM= 0.0
fA= 1.0
FFS = BFFS −fLW−fLC–fM–fA= 46.75 (Eq. 6.7)
Use FFS=45 D= vp/S = 33.75pc/mi/ln Eq (6.6)
After: fA= 3.0
FFS = BFFS −fLW−fLC–fM–fA= 44.75 (Eq. 6.7)
Use FFS=45 Vnew= 2600 Vp= Va/[PHF⋅fHB⋅fp⋅N] = 1795 (Eq. 6.3) D= vp/S = 39.89pc/mi/ln
