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REY [17]
4 years ago
12

A car starts from rest and accelerates at a constant rate after the car has gone 50 m it has a speed of 21 m/s what is the accel

eration of the car
Physics
1 answer:
Leya [2.2K]4 years ago
3 0

Answer:

4.41 m/s^2

Explanation:

(v_f)^2 - (v_i)^2 = 2a * change in distance

(21)^2 - (0)^2 = 2a * 50

a = (21^2)/(2*50)

a = 4.41 m/s^2

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The distance between two parallel wires carrying currents of 10 A and 20 A is 10 cm. Determine the magnitude and direction of th
Marianna [84]

Explanation:

It is given that,

Current in wire 1, I₁ = 10 A

Current in wire 2, I₂ = 20 A

Distance between wires, d = 10 cm = 0.1 m

Force per unit length is given by :

\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}

\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 10\times 20}{2\pi \times 0.1}

\dfrac{F}{l}=0.0004\ N/m

\dfrac{F}{l}=4\times 10^{-4}\ N/m

So, the magnetic force acting per unit length of the wires 4\times 10^{-4}\ N/m. Since, the current is in same direction. So, the force is attractive in nature.

6 0
3 years ago
The motion of a pendulum for which the maximum displacement from equilibrium does not change is an example of simple harmonic mo
Alexeev081 [22]
The statement "<span>The motion of a pendulum for which the maximum displacement from equilibrium does not change is an example of simple harmonic motion." is true. 

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6 0
3 years ago
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A 1500 kg car traveling to the north is slowed down uniformly from initial velocity of 20 m/s by a 6000 N braking force acting o
aev [14]

Answer:

12 m/s

Explanation:

Given data

Mass m= 1500kg

intitial velocity u= 20m/s

force F= 6000N

time t= 2 seconds

Required

The final velocity v

From

Ft= mΔv

Ft= m(u-v)

substitute

6000*2= 1500(20-v)

solve for v

12000= 30000- 1500v

collect like terms

12000-30000= -1500v

-18000= -1500v

divide both sides by  -1500v

v= 18000/1500

v=12 m/s

Hence the velccity is 12 m/s

3 0
3 years ago
Two Force one of 12 Newton and another 24 Newton acts at 90 degree with each other find the resultant of two force and its direc
Leona [35]

Answer:

Fr = 26.83 [N]

Explanation:

To solve this problem we must use the Pythagorean theorem, since the forces are vector quantities, that is, they have magnitude and density. Therefore the Pythagorean theorem is suitable for the solution of this problem.

F_{r}=\sqrt{(12)^{2}+(24)^{2}  } \\F_{r}=26.83[N]

3 0
3 years ago
How does Earth's gravity affect the motion of the moon and satellites
Morgarella [4.7K]

Answer: well it keeps the international space station in orbits around the earth and gravity keeps the moon keep orbiting the earth

Explanation:

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3 years ago
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