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umka2103 [35]
4 years ago
11

The electrical resistance of a wire varies directly as its length and inversely as the square of its diameter. a wire with a len

gth of 200 inches and a diameter of one-quarter of an inch has a resistance of 20 ohms. find the electrical resistance in a 500 inch wire with the same diameter.
Physics
1 answer:
Annette [7]4 years ago
3 0
The electrical resistance of the wire is proportional to its length L and inversely proportional to the square of its diameter, 1/r^2. 

The length of the wire in the problem is changed from 200 inches to 500 inches, so the new length is 2.5 times the initial length:
\frac{L_1}{L_0}= \frac{500}{200}=2.5
the diameter of the wire is not changed, so the new electrical resistance must be 2.5 times the original value:
R_1 = 2.5 R_0 = 2.5 \cdot 20 \Omega =50 \Omega
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In an elastic collision, a 400-kg bumper car collides directly from behind with a second, identical bumper car that is traveling
kirza4 [7]

Answer:

v₁ = 3.5 m/s

v₂ = 6.4 m/s

Explanation:

We have the following data:

m₁ = mass of trailing car = 400 kg

m₂ = mass of leading car = 400 kg

u₁ = initial speed of trailing car = 6.4 m/s

u₂ = initial speed of leading car = 3.5 m/s

v₁ = final speed of trailing car = ?

v₂ = final speed of leading car = ?

The final speed of the leading car is given by the following formula:

v_2=\frac{2m_1}{m_1+m_2}u_1-\frac{m_1-m_2}{m_1+m_2}u_2\\\\v_2=\frac{(2)(400\ kg)}{400\ kg+400\ kg}(6.4\ m/s)-\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(3.5\ m/s)

<u>v₂ = 6.4 m/s</u>

The final speed of the leading car is given by the following formula:

v_1=\frac{m_1-m_2}{m_1+m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\\\v_1=\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(6.4\ m/s)+\frac{(2)(400\ kg)}{400\ kg+400\ kg}(3.5\ m/s)

<u>v₁ = 3.5 m/s</u>

4 0
3 years ago
What is the only possible value of ml for an electron in an s orbital?
Archy [21]

Answer:

  • zero

Explanation:

m_l     is the magnetic quantum number.

The only possible value for the magnetic quantum number for an electron in an s orbital is 0.

The first three quantun numbers are:

  • n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...

  • l : Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.

       This quantum number is related to the type (or shape) of the orbital:

        For s orbitals l=0

        For p orbitals l=1

        For d orbitals l=2

         For f orbitals l=3

In this case, it is an s orbital, so we have l=0.

  • m_l , the third quantum number can have integer values  {from-l}   to    {+l}

       Since, for the s orbitals  l=0 , the only possible value for {m_l} is zero.

4 0
4 years ago
You hold glider AA of mass 0.125 kgkg and glider BB of mass 0.375 kgkg at rest on an air track with a compressed spring of negli
andrew11 [14]

Answer:

The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction  

Explanation:

Inelastic Collision

Given data

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final velocity v1= 0.600 m/s

mass of glider B m2= 0.375kg

initial velocity u2=0

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We know that the expression for the conservation of momentum is given as

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since u1=u2=u=0m/s

u(m1+m2)=m1v1+m2v2

substituting we have

0(0.125+0.0375)=0.125*0.6+0.375*v2

0=0.075+0.375v2

0.375v2=-0.075

v2=-0.075/0.375

v2=-0.2m/s

 The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction      

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6 0
3 years ago
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MissTica

Answer:

Newton's second law states that when a body of mass m is accelerated with force f

then F=ma

this means acceleration of an object depends on both force with which it is moving as well as its mass

8 0
3 years ago
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