Answer:
V₂ = 285 mL
Explanation:
Given data:
Initial volume of bag = 250 mL
Initial temperature = 19.0°C
Final temperature = 60.0°C
Final volume = ?
Solution:
The given problem will be solved by using Charles Law,
This law stated that " The volume of given amount of gas at constant pressure and constant number of moles is directly proportional to its temperature"
Mathematical relationship:
V₁/T₁ = V₂/T₂
Now we will convert the temperature into kelvin.
Initial temperature = 19.0 + 273 = 292K
Final temperature = 60.0 + 273 = 333K
Now we will put the values in formula:
V₁/T₁ = V₂/T₂
250 mL / 292K = V₂/ 333K
0.856 mL /K = V₂/ 333K
V₂ = 0.86×333K. mL /K
V₂ = 285 mL
A scientific law describes an observed occurrence or phenomena.
Answer:
The ratio of acid to conjugate base is outside the buffer range of 10:1.
Explanation:
The Henderson-Hasselbalch equation for a buffer is
![\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}](https://tex.z-dn.net/?f=%5Ctext%7BpH%7D%20%3D%20%5Ctext%7BpK%7D_%7B%5Ctext%7Ba%7D%7D%20%2B%20%5Clog%5Cdfrac%7B%5Ctext%7B%5BA%24%5E%7B-%7D%24%5D%7D%7D%7B%5Ctext%7B%5BHA%5D%7D%7D)
A buffer should have
![\dfrac{1}{10} \leq \dfrac{\text{[A$^{-}]$}}{\text{[HA]}} \leq \dfrac{10}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B10%7D%20%5Cleq%20%5Cdfrac%7B%5Ctext%7B%5BA%24%5E%7B-%7D%5D%24%7D%7D%7B%5Ctext%7B%5BHA%5D%7D%7D%20%5Cleq%20%5Cdfrac%7B10%7D%7B1%7D)
For a solution that is 1.3 mol·L⁻¹ in HF and 1.3 mmol·L⁻¹ in KF, the ratio is
The ratio of acid to conjugate base is 1000:1, which is outside the range of 10:1.
A is wrong. NF is a weak acid.
C is wrong. The two species are a conjugate acid-base pair.
D is wrong. Salts of Group 1 metals are soluble.
Answer:
because it covers a large area as there are more then 1 lakh compounds of organic chemistry.
Answer:1. the junk sculpture rules say the forms have to change every two weeks or be taken clear down. 2. the weather and other people change the forms after they are built
Explanation:
