Question

Bx%7D%7B4%20%7D%20" id="TexFormula1" title=" \frac{x + 1}{3} = \frac{1}{2} + \frac{x}{4 } " alt=" \frac{x + 1}{3} = \frac{1}{2} + \frac{x}{4 } " align="absmiddle" class="latex-formula">

Answer 1

$\bf \cfrac{x+1}{3}=\cfrac{1}{2}+\cfrac{x}{4}\impliedby \begin{array}{llll} \textit{let's multiply both sides by }\stackrel{LCD}{12}\\ \textit{to toss away the denominators} \end{array} \\\\\\ 12\left( \cfrac{x+1}{3} \right)=12\left( \cfrac{1}{2}+\cfrac{x}{4} \right)\implies 4x+4=6+3x\implies x=2$

Answer 2

$\dfrac{x + 1}{3} = \dfrac{1}{2} + \dfrac{x}{4 }|\cdot12 \\\\ 4(x+1)=6+3x\\\\ 4x+4-3x=6\\\\ x=2$