Part 1) Find the measures of angle BGEwe know that
The inscribed angle measures half of the arc it comprises.
so
angle BGE=(1/2)*[arc EB]
Part 2) Find the angle BDG
we know that
The measure of the external angle is the semi-difference of the arcs that it covers.
so
angle BDG=(1/2)*[arc GEB-arc GB]
Answer:
Where is the question?
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello, when you have an equation like y = ax+b you know that this is a line.
In this example, the function is defined in two different intervals.
For x < 1 this is the line y = 4 + x
and for x>=1 this is the line y = 4 - 2x
At the frontier, x= 1, we have 4+1=5 on one side and 4-2=2 on the other side, we we expect a "jump" in the graph.
Except that "jump"you just have to draw lines, so if you have two points you can draw them right.
For x<1, the line is passing by (-4,0) and (0,4)
And you have to stop for x<1 so the point (1,5) is not on the graph.
for x>=1 the points (1,2) and (2,0) are on the graph and we just have to draw the line.
I attached the graph.
Thanks
First you need to find the 3rd angle of the triangle
180 - 86 - 46 = 48
and then subtract the answer by 180 (because it’s a straight line)
180 - 48 = 132
so 132
83.21.....................
