It's about 3 (3 13/33) to be exact
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3

Note: Negative time (-0.2) is not valid
B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.
The second way is to FOIL them out. When you check B you get

combine your like terms and you have your original expression of

Hope that helps
Area = ab Sin O
= (63)(76) Sin 63 degrees
= 4266 square cm.
<span>45(v−7)=2
45v - 315 = 2
45v = 317
v = 317/45
v = 7 2/45 (7 and 2/45)</span>