The temperature of an object is a measure of the average thermal energy of the molecule in the object true or false

A student pulls a 50-newton sled with a force having a magnitude of 15 newtons. What is the magnitude of the force that the sled

Simora [160]

Answer:

Force = 35 N

Explanation:

From Newton's third law of motion, the boy must apply a force greater than the weight of the sled to lift it.

weight of sled = mg

where m is its mass and g the force of gravity on it.

weight of sled = 50 N

Force applied by the boy on the sled = 15 N

Since the force applied on the sled by the boy is lesser than the weight of the sled, then;

Force that the sled exerts on the student = 50 - 15

= 35 N

The force exerted by the sled on the student is 35 N.

5 0

3 years ago

In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 4.8 m/s at an

tensa zangetsu [6.8K]

The equation to be used here is the trajectory of a projectile as written below:

y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
θ is the angle of trajectory or launch angle
g is 9.81 m/s²
v is the initial velcity

Since the angle is below horizontal, let's use the minus equation. Substituting the values:

- 0.8 m = xtan15° - (9.81 m/s²)x²/2(4.8 m/s)²(cos15°)²
Solving for x,
x = 2.549 m

However, we only take half of this distance because it was specified that the distance asked before bouncing. Hence, the horizontal distance is equal to 1.27 m.

5 0

4 years ago

If ball C is 3 times the volume of ball D and ball D has 1/3 the mass of ball C, which has the greater density?

Alex Ar [27]

Answer:

They have same density

Explanation:

The density of an object is defined as

$d=\frac{m}{V}$

where

m is the mass of the object

V is its volume

Let's call $m_c$ and $V_c$ the mass and the volume of ball C, respectively. Therefore, the density of ball C is:

$d_c = \frac{m_c}{V_c}$

We know that the volume of ball C is 3 times the volume of ball D, so

$V_c = 3 V_d \rightarrow V_d = \frac{V_c}{3}$

And we also know that ball D has 1/3 the mass of ball C:

$m_d = \frac{m_c}{3}$

So, the density of ball D is:

$v_d = \frac{m_d}{V_d}=\frac{m_c/3}{V_d/3}=\frac{m_c}{V_c}=d_c$

Therefore, the two balls have same density.

6 0

4 years ago

Plz answer asap I need all of the answer

Ugo [173]

Answer:

Turned up side down

Explanation:

3 0

3 years ago

True or false: (a) Maxwell's equations apply only to fields that are constant over time.(b) The wave equation can be derived fro

Andre45 [30]

Answer:

(a) False

(b) True

(c) True

(d) True

(e) True

(f) True

Explanation:

(a) Maxwell's equations not only applies to constant fields but it applies to both the fields, i.e., Time variant field as well as Time Invariant field.

(b) We make use of the Modified form of the Ampere's law and Faraday's Law to derive the wave equation.

(c) Electromagnetic waves contains both the electric and magnetic fields and these fields oscillates at an angle of $90^{\circ}C$ to the direction of wave propagation.

(d) In free space both the electric and magnetic fields are in phase while considering electromagnetic waves.

(e) In free space or vacuum, the expression for the speed of light in terms of electric and magnetic field is given as:

$c = \frac{E}{B}$

Thus the ratio of the magnitudes of the electric and magnetic field vectors are equal to the speed of light in free space.

(f) In free space or in vacuum the energy density of the electromagnetic wave is divided equally in both the fields and hence are equal.

3 0

3 years ago