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3 years ago

What does the number, or density, of field lines on a source charge indicate?

Physics

2 answers:

Harrizon [31]3 years ago

6 0

Hello.

The answer: C. amount of charge on the source charge

The field lines all represent the movements of field charges. The more crowded the field lines or the more density of electric field the higher is the magnitude of the source charge.

Have a nice day.

Natali [406]3 years ago

3 0

The number or density of field lines on a source charge indicates the amount of charge on the source charge.

Answer: Option C

<u>Explanation: </u>

The source charge is the point from which the charge lines or the lines of energy will be started. So the number of lines emitted from the point charge or the source charge will indicate the strength of the source charge.

Also by measuring the density of the source charge i.e., the number of lines emitted per unit volume or the field lines which is the measure of lines emitted per unit area also indicate the strength of the source charge. So these strength are nothing but the amount of charge present in the source charge.

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hich one of the following statements could be an operational definition of electric current?View Available Hint(s)Which one of t

klemol [59]

Answer:

it is True as the operational definition of electric current.

Explanation:

The definition of electric current is

I = dQ / dt

By convention the direction of the current is the direction in which a positive charge flows.

The initial expression is the derivative that is the change of the load in the unit of time and this occurs in a given cross-sectional cable.

The proposed definition is the same as this, so it is True as the operational definition of electric current.

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3 years ago

A house is lifted from its foundations onto a truck for relocation. The house is pulled upward by a net force of 2850 N. This fo

Gwar [14]

Answer:

m = 95000 kg

Explanation:

Given that,

Net force acting on the house, F = 2850 N

Initial speed, u = 0

Final speed, v = 15 cm/s = 0.15 m/s

We need to find the mass of the house. Let the mass be m. We know that the net force is given by :

F = ma

Where

a is the acceleration of the house.

So,

$F=m\dfrac{v-u}{t}\\\\m=\dfrac{Ft}{(v-u)}\\\\m=\dfrac{2850\times 5}{(0.15-0)}\\\\m=95000\ kg$

So, the mass of the house is equal to 95000 kg.

3 0

3 years ago

According to Kepler's harmonic law, Neptune would have a _________ orbit around the Sun than Mercury.

chubhunter [2.5K]

Neptune would have a slower orbit i just did this

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3 years ago

Read 2 more answers

A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma

Oksanka [162]

Answer:

Explanation:

The momentum of the first piece = m v =- m x 31 i kg m/s in - x direction direction

The momentum of the second piece = -m x 31 j kg m /s in Y - direction

Total momentum = - 31 m( i + j )

To conserve momentum , the third piece must have momentum equal to this

and opposite to it

So momentum of the third piece = 3m x V = 31 m ( i +j )

V = 31/3 ( i + j ) =

Magnitude of velocity V = √2 x 31/ 3 = 14.6 m / s

Its direction will be towards the vector i + j ie 45° from x - axis in positive direction

4 0

3 years ago

A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force

Ghella [55]

Answer:

The linear velocity of the object is 8.71 m/s.

Explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

centripetal force, F = 23 N

Centripetal force is given by;

$F_c = \frac{mv^2}{r}\\\\$

where;

v is the linear velocity of the object

$F_c = \frac{mv^2}{r}\\\\mv^2 = F_cr\\\\v^2 = \frac{F_cr}{m}\\\\v= \sqrt{\frac{F_cr}{m}} \\\\v= \sqrt{\frac{23*3.3}{1}}\\\\v = 8.71 \ m/s$

Therefore, the linear velocity of the object is 8.71 m/s.

4 0

3 years ago