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posledela
2 years ago
11

What is the total precentage of radiation that is reflected by earths atmosphere

Physics
1 answer:
Furkat [3]2 years ago
6 0

Around 48 % of the incoming solar energy passes through the atmospheric layer of the earth. The water vapor,ozone and dust present in the atmosphere absorbs 23 percent of incoming solar energy .Thus about 71% of the incoming solar radiation is absorbed by the earth. The rest 29% of the incoming solar radiation is reflected back into the space.

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Sveta_85 [38]

txt now you need to add to 14 to those two to get it between the 14 and 19 and basically you will just be able to do this the liquid is 45 as you know that's all I got to say for you is that you have to answer the phone for you equational to pay

7 0
3 years ago
Imagina que compras una placa rectangular de metal de 2mm de alto, 10mm de ancho x 50mm de largo, y una masa de 0.02kg. El vende
shusha [124]

Answer:

Densidad de la placa = 20 g/cm³.

La placa no es de oro.

Explanation:

Para encontrar la densidad de la placa rectangular primero debemos hallar su volumen:

V = 2 mm*10 mm*50 mm = 1000 mm^{3}*\frac{1 cm^{3}}{(10 mm)^{3}} = 1 cm^{3}      

Ahora, encontremos al densidad de la placa:

d = \frac{m}{V} = \frac{20 g}{1 cm^{3}} = 20 g/cm^{3}

Dado que la densidad del oro es 19.32 g/cm³ y que la densidad de la placa rectangular calculada es 20 g/cm³, podemos decir que dicha placa no es de oro.                  

Espero que te sea de utilidad!

6 0
3 years ago
What Could be the control in an experiment to measure the effects of gas additives on fuel
alina1380 [7]
Well,

A control in an experiment would basically be the "normal" version of your test subjects.

In a drug testing experiment with people, the control group would be the people who don't take the drug.

In an experiment on the effects of salt on potatoes, the control group would be a potato without salt on it.

So in an experiment to measure the effects of gas additives on fuel, the control would be fuel without additives.
8 0
3 years ago
A 7.0kg object rests on a horizontal frictionless surface. What is the magnitude of the horizontal
sukhopar [10]

Answer:

16.1 N

Explanation:

From the question,

F = ma.............................. Equation 1

Where F = horizontal force, m = mass of the object, a = acceleration .

Given: m = 7.0 kg, a = 2.3 m/s²

Substitute this values into equation 1

F = (7.0×2.3)

F = 16.1 N.

Hence the magnitude of the horizontal force is 16.1 N

6 0
2 years ago
A child pulls a sled up a snow-covered hill. The child does 504 J of work on the sled. If the child walks 15 m
Juliette [100K]

Answer: F = 33.6 N

Explanation: work = force · distance or W = F·s

Force F = W/s = 504 J/15 m

7 0
2 years ago
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