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3 years ago

On the moon, what would be the force of gravity acting on an object that has a mass of 7kg?

Physics

1 answer:

Kruka [31]3 years ago

6 0

Answer:

Force of gravity, F = 70 N

Explanation:

It is required to find the force of gravity acting on an object that has a mass of 7 kg. Force of gravity always acts in downward direction.

The force of gravity is equal to the weight of an object. It is given by :

$F=mg$

g = acceleration due to gravity, for Earth, g = 10 m/s²

So,

$F=7\times 10\\\\F=70\ N$

So, 70 N of force of acting on an object.

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A proton moving eastward with a velocity of 5. 0 × 103 m/s enters a magnetic field of 0. 20 t pointing northward. what is the ma

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The magnitude of the force is 1.6*10^-16 N. The direction of force is upward.

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The strength of the force increases when all the force is pulling in the same direction. When force is exerted on an item from different angles, the force's strength reduces. The amount that encapsulates the force's strength is known as its magnitude.

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2 years ago

What is the specific heat capacity of water?

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The specific heat of water is 4.186.

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3 years ago

In a generator, as the magnet spins, opposite poles of the magnet push the electrons in opposite directions. This back-and-forth

Natali [406]

C) alternating current .
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3 years ago

Read 2 more answers

A tank initially holds 100 gallons of salt solution in which 50 lbs of salt has been dissolved. A pipe fills the tank with brine

olga_2 [115]

Answer:

A. 171.24 Ibs

Explanation:

To find the amount of salt in the tank,

Let Q = Amount of salt in the mixture

And let 100 + (3-2)t = 100 + t be the volume of mixture at anytime t.

Rate of gain - Rate of loss = dQ / dt

Concentration of salt = Q / (100+t)

For the linear differential equation,

dQ / dt = 3(2) - 2 [Q/ (100 + t)]

dQ /dt + Q [2 / (100 + t)] = 6

The general solution of the linear differential equation is:

Q (i.f) = ∫ A(t) (i.f) dt + C

Therefore,

i.f = e ^ ∫ P(t) dt

And P(t) = 2 / (100 + t)

i.f = e ^ ∫ 2 / (100 + t)

= e ^ 2㏑ (100 + t)

= e ^ ㏑ (100 + t) ^2 = (100 + t) ^2

Q(100 + t) ^ 2 = ∫6 (100 + t) ^2 dt + C

Q(100 + t) ^2 = 2(100 + t) ^ 3 + C

When t = 0, Q = 50

Therefore,

50( 100) ^2 = 2(100) ^3 + C

C = -1.5 * 10 ^6

therefore, when t = 30,

Q (100 + 30) ^2 = 2(100 + 30) ^3 - 1.5 * 10 ^6

Q (400) ^2 = 2(130) ^3 - 1.5 * 10 ^6

Q = 171.24 Ibs

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3 years ago

The atomic number of a nucleus decreases during which nuclear reactions?

Goryan [66]

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