If we dissolve 10 mL of acid into a beaker of water. The acid will be diluted.
Since the number of moles of acid will not change, we can use this formula:
M1 V1 = M2 V2
Where M is the concentration of the acid in the solution
V1 = 10 mL
and
V2 = Vwater + 10
If we add an additional 5 mL of acid, the new concentration of the acid will be:
M = (M1 (5mL) + M2 (Vwater + 10mL)) / (5mL + Vwater + 10mL)
The concentration of acid in the new solution will increase.
Answer:
Option C. Neutral
Explanation:
A solution that does not change the colour of litmus paper is a neutral solution. Thus, the solution does not conduct electricity because there is no free ions in the solution
