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galben [10]
3 years ago
10

Suppose you see a crescent Moon. How do you know if it is waxing or waning?

Chemistry
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

waxing is in the evening and waning is in the morning if you cant see the moon in the evening it is waning if you can see it in the evening it is waxing

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Lab: Limiting Reactant and Percent Yield
creativ13 [48]

Answer : If a substance is the limiting reactant, then it limits the formation of products because in the reaction it is present in limited amount.

Explanation :

While observing a chemical reaction, we can tell about whether a reactant is limiting or excess.

Step 1 : first write the chemical reaction and then balanced the chemical equation.

C_2H_4+H_2\rightarrow C_2H_6

Step 2 : convert the given masses into the moles if mass of C_2H_4 is 10.5 g and molar mass of C_2H_4 is 28 g/mole and the mass of hydrogen is 0.40 g and molar mass of hydrogen is 2 g/mole.

\text{moles of }C_{2}H_{4}=\frac{10.5g}{28g/mole}=0.375moles

\text{moles of }H_{2}=\frac{0.40g}{2g/mole}=0.20moles

Step 3 : Now we have to determine the limiting reagent and excess reagent.

\text{ moles of }C_{2}H_{4}\text{ in excess}=0.375-0.20=0.175\text{moles}

Now we conclude that C_{2}H_{4} is the limiting reagent and hydrogen is an excess reagent.

Hypothesis :

Limiting reagent : It is the reagent in the chemical reaction that is totally consumed when the chemical reaction is complete.  Limiting reagent limits the formation of products.

7 0
2 years ago
Read 2 more answers
In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th
Reptile [31]

Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

Molar mass octane = 114.23 g/mol

Mass CO2 =1.84 kg = 1840 grams

Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

Moles octane = 6.145 moles

Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

4 0
3 years ago
Please answer!! I WILL GIVE EXTRA POINTS AND BRAINLIEST
sveta [45]
The answer is D I believe
5 0
3 years ago
Read 2 more answers
My teacher is grading this soon can someone help me ASAP!
Stolb23 [73]

10. You demonstrated the difference in density of the two objects. It is a physical property.

11. First calculate the density for all of them: density = mass/volume

Density:

A. 5/6 g/ml

B. 10/9 g/ml

C. 15/16 g/ml

D. 20/10 g/ml

If the density of the substance is higher than the density of the substance it is put in, then it will sink. So substances B and D will sink in water, as their densities are higher than 1 g/ml.

12. Ammonia weighs less than water does-- for example, the weight of 8 gallons of ammonia will be equivalent to the weight of 5 gallons of water.

Hope this helped!

3 0
3 years ago
What is the number of electrons in oxygen
Semmy [17]
Answer for your question is;

2,6 = 8
The first shell is 2 electrons the other shell is 6 electrons
6 0
2 years ago
Read 2 more answers
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