Answer:
a. K = [H+][NO2-]/[HNO2]
Explanation:
The computation of the expression of the equilibrium constant is shown below:
Given that the weak acid is HNO_2 that exist in the solution that aqueous
The dissociation equation of 

Now
Acidionization constant i.e.
![k_a = \frac{[NO_{2}^{-}][H^{+}]}{HNO_{2}}](https://tex.z-dn.net/?f=k_a%20%3D%20%5Cfrac%7B%5BNO_%7B2%7D%5E%7B-%7D%5D%5BH%5E%7B%2B%7D%5D%7D%7BHNO_%7B2%7D%7D)
Therefore the correct option is a.
Hence, the same is to be considered
Answer:
2CO₂ ⇄ 2CO + O₂.
Explanation:
- <em>The equilibrium constant (Keq)</em> for a reaction is the ratio of the concentration of the products to the reactants, each one is raised to each molar coefficient.
So, for Keq = [CO]²[O₂]/[CO₂]²,
It is clear that the products are CO and O₂, while the reactant is CO₂.
So, the reaction for this is:
<em>2CO₂ ⇄ 2CO + O₂.</em>
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