The molar mass of the weak acid is calculated as follows
by use of an example of monoprotic weak such as CH3COOH reacting with NaOH
that is NaOH + CH3COOH = CH3COONa + H2O
calculate the moles of NaOH used
= molarity x volume/1000
= 44.6 ml x 0.100/ 1000 = 4.46 x10^-3 moles
by use of mole ratio between NaOH to monoprotic acid which is1:1 the moles of monoprotic acid is also 4.46 x10^-3 moles
molar mass is therefore = mass/ moles = 0.139 g/ (4.46 x10^-3) = 31.17 g/mol
Answer:
the right side of the periodic table are metals while the left side are non metals (with the exception of hydrogen)
Answer is: at higher temperatures reaction will go to the right (forward), more products (C₂H₄ and H₂) will be produce, because this is endothermic reaction (ΔH<span> is positive, </span>energy is consumed) and according Le Chatelier's principle <span>heat is included as a reactant. </span> .
Answer:
I dont get it what am i supposed to do?
Explanation:
Solution
Given mass of FeBr2 = 85.5 g
Molar mass of FeBr2 = 215.65
No. of Moles of FeBr2 = Given Mass / Molar mass = 85.5 / 215.65
No. of Moles = 0.3964
Given Volume is 450 mL i.e. 0.450 L
Now Concentration = 0.3964/0.450
Hence Concentration = 0.881 mol/L
