Ask question

Ask question

All categories

Mekhanik [1.2K]

3 years ago

10

what is the net force if you push a cart to the right with 5N of force and a friend pushes the cart to the left with 5N of force

1 answer:

Novosadov [1.4K]3 years ago

4 0

The net force will be zero. Since the forces are in opposite direction and equal amount, they will cancel out.

You might be interested in

If a force of 25 N is applied to an object with a mass of 8 kg, the object will accelerate at

Blizzard [7]

3.13 m/s2
.
the formula for acceleration is as follows:
force/mass = acceleration
-
so 25/8 = 3.13

3 0

2 years ago

Which examples are simple machines?

frozen [14]

A hammer and a pulley

4 0

2 years ago

Two cars are moving towards each other and sound emitted by first car with real frequency of 3000 hertz is detected by a person

sertanlavr [38]

Answer:

v ’= 21.44 m / s

Explanation:

This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s

f ’= f (v + v₀) / (v- $v_{s}$ )

where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer

in this exercise both the source and the observer are moving, we will assume that both have the same speed,

v₀ = v_{s} = v ’

we substitute

f ’= f (v + v’) / (v - v ’)

f ’/ f (v-v’) = v + v ’

v (f ’/ f -1) = v’ (1 + f ’/ f)

v ’= (f’ / f-1) / (1 + f ’/ f) v

v ’= (f’-f) / (f + f’) v

let's calculate

v ’= (3400 -3000) / (3000 +3400) 343

v ’= 400/6400 343

v ’= 21.44 m / s

3 0

2 years ago

Find the magnitude of the sum

shusha [124]

Answer:

$\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m$

Explanation:

<u>Sum of Vectors in the Plane</u>

Given two vectors

$\displaystyle \vec{v_1}\ ,\ \vec{v_2}$

They can be expressed in their rectangular components as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_2}=$

The sum of both vectors can be done by adding individually its components

$\displaystyle \vec{v_1}+\vec{v_2}=$

If the vectors are given as a magnitude and an angle $(M\ ,\ \theta )$ , each component can be found as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_2}=$

The first vector has a magnitude of 3.14 m and an angle of 30°, so

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=$

The second vector has a magnitude of 2.71 m and an angle of -60°, so

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=$

The sum of the vectors is

$\displaystyle \vec{v_1}+\vec{v_2}=$

$\displaystyle \vec{v_1}-\vec{v_2}=$

Finally, we compute the magnitude of the sum

$\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{(4.08)^2+(-0.78)^2}$

$\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{17.25}$

$\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m$

3 0

2 years ago

A solid weighs 200N in air, 150N in water and 170N in a liquid. Find relative density of solid, relative density of liquid and d

fomenos

Answer:

$\rho_{s} = 4$

$\rho_{l} = 0.6$

$\rho{liq} = 600 kg/m^{3}$

Given:

Weight of solid in air, $w_{sa} = 200 N$

Weight of solid in water, $w_{sw} = 150 N$

Weight of solid in liquid, $w_{sl} = 170 N$

Solution:

Calculation of:

1. Relative density of solid, $\rho_{s}$

$\rho_{s} = \frac{w_{sa}}{w_{sa} - w_{sw}}$

$\rho_{s} = \frac{200}{200 - 150} = 4$

2. Relative density of liquid, $\rho_{l}$

$\rho_{l} = \frac{w_{sa} - w_{sl}}{w_{sa} - w_{sw}}$

$\rho_{l} = \frac{200 - 170}{200 - 150} = 0.6$

3. Density of liquid in S.I units:

Also, we know:

$\rho{l} = \frac{\rho_{liq}}{\rho_{w}}$

where

$= {\rho_{liq}}$ = density of liquid

$= {\rho_{w}} = 1000 kg/m^{3}$ = density of water

Now, from the above formula:

$0.6 = \frac{\rho_{liq}}{1000}$

$\rho{liq} = 600 kg/m^{3}$

3 0

2 years ago