If the gravitational force were<span> decreased by half, there would be lack of gravity on earth. Hence, it would basically affect the velocity, speed, and the distance travelled in any direction by basketball players and the ball. The basketball would bounce higher and come down in a slower speed. Whereas for the players, they would be able to leap higher from the floor.</span><span> </span>
The momentum of the truck is given by:
p = mv
p = momentum, m = mass, v = velocity
There isn't too much work to do here; the truck is at rest, therefore its velocity is 0. This means the product of m and v is 0, giving the momentum as 0.
The unconditioned stimulus (UCS) for Tab the dog is: B. The flowers and fence.
<h3>The types of stimuli.</h3>
In Science, the two (2) stimuli that are repeatedly paired in classical conditioning include:
<h3>What is an unconditioned stimulus?</h3>
An unconditioned stimulus can be defined as a stimulus that is capable of naturally triggering a response, before or without any conditioning while it elicit a specific response without learning.
- This ultimately implies that, an unconditioned stimulus leads to an automatic response in a living organism such as a dog.
In this scenario, the unconditioned stimulus (UCS) for Tab the dog is simply the flowers and fence.
Read more on unconditioned stimulus here: brainly.com/question/24868138
The correct answer to this problem is C
Answer:
a) λ = 2 m
, c) f = 50 Hz
Explanation:
When a string is fixed at the ends the wave is reflected at each end, giving rise to a standing wave.
Since we extract them are fixed we have nodes at these points, the wavelength in the string is
fundamental λ = 2L
2nd harmonic λ= 2L / 2
3 harmonica λ= 2L / 3
a and b) from aui we can find the wavelength
λ = 2 3/3
λ = 2 m
c) the speed of the wave is related to the frequency and wavelength
v = λ f
f = v / λ
f = 100/2
f = 50 Hz
d) the acceleration can be found with the equations
a = d²y / dt²
the standing wave equation is
y = 2A sin kx cos wt
a = -2A w² sin kx cos wt
the acceleration is maximum when the cosine is ±1
A = 2A w² sin kx
the oscillatory part indicates that the wave moves, if we make this maximum vine, they relate it to
a = 2A w²
w = 2πf
A = 0.2 cm = 0.002 m
a = 2 0.002 (2π 50)²
a = 98.7 m / s