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3 years ago

When an automotive battery is fully charged, the sulfuric acid and water mixture will have a specific gravity of about

Physics

2 answers:

kari74 [83]3 years ago

8 0

Answer:1.3

Explanation:

Took the test on Penn foster

siniylev [52]3 years ago

6 0

When an automotive battery is fully charged, the mixture of water
and sulfuric acid in it has a specific gravity of about 1.3 .

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You walk six blocks east along 12th Street, then three blocks west, then one block east, then six blocks east, then seven blocks

Oksana_A [137]

Displacement depends upon the path taken as it is a vector.

From your problem above we would have a total displacement of;
Defining +x direction as east and -x direction as west

6east-3west+1east+6east-7west

6-3+1+6-7=3 blocks east or + x-direction

So even though they walked a total of 17 blocks it ends up only being 3 blocks total in +xdirection that was travelled by displacement.

Any questions please ask.

5 0

2 years ago

A power plant uses Uranium<br> to produce energy

antoniya [11.8K]

Answer:

how is that a question?

Explanation:

yeah i dunno the answer cause thats not a question

7 0

3 years ago

The specification limits for a product are 8 cm and 10 cm. A process that produces the product has a mean of 9.5 cm and a standa

My name is Ann [436]

Answer:

The value of Cpk is 0.83.

Explanation:

Given that,

Upper specification limits = 10 cm

lower specification limits = 8 cm

Mean = 9.5

Standard deviation = 0.2 cm

We need to calculate the process capability

Using formula of Cpk

$Cpk=min(\dfrac{USL-mean}{3\times SD}, \dfrac{mean-LSL}{3\times SD})$

Put the value into the formula

$Cpk=min(\dfrac{10-9.5}{3\times0.2}, \dfrac{9.5-8}{3\times0.2})$

$Cpk=min(0.83,2.5)$

$Cpk=0.83$

Hence, The value of Cpk is 0.83.

4 0

2 years ago

The point is at the edge of the disk and the component bodies are:

Murrr4er [49]

Answer:

a. A uniform disk of radius and mass .

Explanation:

The moment of inertia I of an object depends on a chosen axis and the mass of the object. Given the axis through the point, the inertia will be drawn from the uniform disc having a radius and the mass.

4 0

3 years ago

A capacitor with initial charge q0 is discharged through a resistor. a) In terms of the time constant τ, how long is required fo

-BARSIC- [3]

Answer:

It would take $\tau(\ln 9 - \ln 8)$ time for the capacitor to discharge from $q_0$ to $\displaystyle \frac{8}{9} \, q_0$ .

It would take $\tau(\ln 9 - \ln 7)$ time for the capacitor to discharge from $q_0$ to $\displaystyle \frac{7}{9}\, q_0$ .

Note that $\ln 9 = 2\,\ln 3$ , and that $\ln 8 = 3\, \ln 2$ .

Explanation:

In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is $\tau$ , and the initial charge of the capacitor be $q_0$ . Then at time $t$ , the charge stored in the capacitor would be: