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2 years ago

9

A lack of precision in scientific measurement typically arises from?

1 answer:

PtichkaEL [24]2 years ago

6 0

Answer:

limitations of the measuring instrument.

Explanation:

Hope this helps

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The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is<br> J.

Jlenok [28]

Hello!

We have the following data:

KE (Kinetic Energy) = ? (in Joule)
m (mass) = 0.5 Kg
v (speed) = 10 m/s

<span>Formula to calculate kinetic energy:

</span> $KE = \frac{1}{2} *m*v^2$
<span>
Solving:

</span> $KE = \frac{1}{2} *m*v^2$

$KE = \frac{1}{2} *0.5*10^2$

$KE = \frac{1}{2} *0.5*100$

$KE = \frac{50}{2}$

$\boxed{\boxed{KE = 25\:Joule}}\Longleftarrow(kinetic\:energy\:of\:a\:ball)\end{array}}\qquad\quad\checkmark$

I hope this helps! =)

4 0

3 years ago

Read 2 more answers

An object is thrown upwards with a velocity of 3 meters per second, such that the only force acting on it is gravity (accelerati

3241004551 [841]

Answer:

Correct answer: A.) V = - 16.6 m/s down

Explanation:

Given:

V₀ = 3 m/s initial velocity

t = 2 seconds

g = 9.8 m/s²

V(t) = V(2) = ?

The movement described is a vertical upward shot

For velocity at any time is valid the next formula

V = V₀ - g · t

V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down

Under condition that it has a enough drop height with respect to the ejection point.

God is with you!!!

3 0

4 years ago

Read 2 more answers

Some believe that the positions of the planets at the time

laila [671]

Answer:

$1.4007\times 10^{-8}\ N$

$1.50075\times 10^{-6}\ N$

$0.000000667\ N$

Explanation:

$m_1$ = Mass of baby = 3 kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Distance between objects

Gravitational force of attraction is given by

$F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 70\times 3}{1^2}\\\Rightarrow F=1.4007\times 10^{-8}\ N$

The force between baby and obstetrician is $1.4007\times 10^{-8}\ N$

$F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(6\times 10^{11})^2}\\\Rightarrow F=1.50075\times 10^{-6}\ N$

The force between the baby and Jupiter is $1.50075\times 10^{-6}\ N$

$F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(9\times 10^{11})^2}\\\Rightarrow F=0.000000667\ N$

The force between the baby and Jupiter is $0.000000667\ N$

7 0

3 years ago

What is the speed, in m/s, of a wave on a cord if it has a wavelength of 4m and a period of 0.5 s

Fittoniya [83]

Using v=Π/p = 4/0.5 = 8ms-¹

8 0

3 years ago

Use Einstein’s energy equation to solve the following problem. Recall that the speed of light is 3 x 108 m/s. If a 5.0-kg stone

Blizzard [7]

E =mc²

= (5.0-kg)(3 x 10^8 m/s)²

= (5.0-kg) (9×10^16m²/s²)

E =4.5×10^17 J

7 0

3 years ago

Read 2 more answers