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Savatey [412]
3 years ago
8

This is how manganese appears in the periodic table. The arrow is pointing to the atomic of manganese.

Physics
2 answers:
Liula [17]3 years ago
5 0
The way an element is shown in the periodic table is called the element's symbol. In the case of manganese, it is Mn. Other information shown alongside the element's symbol is the atomic mass, which for manganese is 55, and the atomic number of the element, which for manganese is 25.
nalin [4]3 years ago
4 0
The answer is symbol :)
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In a physics lab experiment, a compressed spring launches a 24 g metal ball at a 35o angle above the horizontal. Compressing the
Levart [38]

Answer:

k = 45.95 N/m

Explanation:

First, we will find the launch speed of the ball by using the formula for the horizontal range of the projectile.

R = \frac{v_{o}^{2}\ Sin\ 2\theta}{g} \\\\v_{o}^{2} = \frac{Rg}{Sin\ 2\theta}\\

where,

Vo = Launch Speed = ?

R = Horizontal Range = 5.3 m

θ = Launch Angle = 35°

Therefore,

v_{o}^{2} = \frac{(5.3\ m)(9.81\ m/s^{2})}{Sin\ 2(35^{o})}\\

v₀² = 55.33 m²/s²

Now, we know that the kinetic energy gain of ball is equal to the potential energy stored by spring:

Kinetic\ Energy\ Gained\ By\ Ball = Elastic\ Potential\ Energy\ Stored\ in \ Spring\\\frac{1}{2}mv_{o}^{2} = \frac{1}{2}kx^{2}\\\\k = \frac{mv_{o}^{2}}{x^2} \\

where,

k = spring constant = ?

x = compression = 17 cm = 0.17 m

m = mass of ball = 24 g = 0.024 kg

Therefore,

k = \frac{(0.024\ kg)(55.33\ m^2/s^2)}{(0.17\ m)^2} \\

<u>k = 45.95 N/m</u>

4 0
3 years ago
A rope is shaken and produces 2 waves each second. Calculate the time period of the rope waves.
motikmotik

Answer:

0.5 s

Explanation:

From the question given above, the following data were obtained:

Number of circle (n) = 2

Time (t) = 1 s

Period =?

Period of a wave is simply defined as the time taken to make one complete oscillation. Mathematically, it can be expressed as:

T = t / n

Whereb

T => is the period

t => is the space time

n => is the number of circle or oscillation.

With the above formula, we can obtain the period of the wave as follow:

Number of circle (n) = 2

Time (t) = 1 s

Period =?

T = t / n

T = 1 / 2

T = 0.5 s

Thus, the period of the wave is 0.5 s

7 0
3 years ago
The relationship between sharks and remoras is characterized<br><br>TRUE <br>   OR<br>FALSE
Damm [24]
False, sharks and remoras have a symbiotic relationship. The remora removes parasites from the sharks scales, and the shark provides protection for the remora
8 0
3 years ago
In this lab you will use a cart and track to explore various aspects of motion. You will measure and record the time it takes th
Keith_Richards [23]

It is given that by using track and cart we can record the time and the distance travelled and also the speed of the cart can be recorded. With all this data we can solve questions on the laws of motion.  

Like using the first law of motion we can determine the force of gravity acting on the cart that has moved a certain distance and the velocity or the speed of card has already been registered and since time is known putting the values in formula would help us calculate the gravitational pull acting on cart.

3 0
3 years ago
Read 2 more answers
If a gas has a gage pressure of 156 kPa, it is absolute pressure is approximately
Art [367]
In the given question, one important information for getting to the actual solution is not given and that is the atmospheric pressure. To find the approximate absolute pressure, it is needed to add the value of atmospheric pressure with the gage pressure.
Atmospheric pressure = 100 kPa
Then
Absolute pressure = 156 + 100 kPa
                             = 256 KPa.
5 0
3 years ago
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