Two charged spheres are on a frictionless horizontal surface when does the charge of +3.0•10^-6C. The other has a +6.0•10^-6C ch
arge. Sketch the two spheres showing off all forces on them. Make the length of your force arrows proportional to the strength of the forces.
2 answers:
Answer:
the diagram is in the attached file. FN is the normal force, Fe is the electric force and Fg is the force of gravity.
Explanation:
According to Newton's Third Law, also called the Principle of Action and Reaction, which says that if a body A exerts an action on a body B, it will perform on A body the same and in the opposite direction, in this case, the magnitude of the electrical forces are equal but opposite, that is, of opposite sign. The exercise does not provide the information to be able to compare the vertical forces with the electrical one, it can be assumed that since the spheres are in equilibrium, the vertical forces are equal to zero.
You might be interested in
Answer:
T₂ = 123.9 N, θ = 66.2º
Explanation:
To solve this exercise we use the law of equilibrium, since the diaphragm does not appear, let's use the adjoint to see the forces in the system.
The tension T1 = 100 N, we create a reference frame centered on the pole
X axis
T₁ₓ - = 0
T_{2x}= T₁ₓ
Y axis y
T_{1y} + T_{2y} - 200N = 0
T_{2y} = 200 -T_{1y}
let's use trigonometry to find the component of the stresses
sin 60 = T_{1y} / T₁
cos 60 = t₁ₓ / T₁
T_{1y} = T₁ sin 60
T1x = T₁ cos 60
T_{1y}y = 100 sin 60 = 86.6 N
T₁ₓ = 100 cos 60 = 50 N
for voltage 2 it is done in the same way
T_{2y} = T₂ sin θ
T₂ₓ = T₂ cos θ
we substitute
T₂ sin θ= 200 - 86.6 = 113.4
T₂ cos θ = 50 (1)
to solve the system we divide the two equations
tan θ = 113.4 / 50
θ = tan⁻¹ 2,268
θ = 66.2º
we caption in equation 1
T₂ cos 66.2 = 50
T₂ = 50 / cos 66.2
T₂ = 123.9 N
Answer:
Explanation:
Given
Power Supplied [/tex]
Efficiency of the motor
and
So, vacuum cleaner delivers a power of