H = 11 m, the vertical distance that the bullet falls.
Initial vertical velocity = 0
Horizontal velocity = 144.7 m/s
The time, t, taken to fall 11 m is given by
(1/2)*(9.8 m/s²)*(t s)² = (11 m)
4.9t² = 11
t = 1.4983 s
If aerodynamic resistance is ignored, the horizontal distance traveled before the bullet hits the ground is
d = (144.7 m/s)*(1.4983 s) = 216.8 m
Answer: 216.8 m
Answer:
average speed is 0.159 m/s
average velocity = 0.0011 m/s
Explanation:
given data
time = 41.6 s
total distance = 6.65 m
length = 0.0463 m
to find out
average speed and the magnitude average velocity
solution
we know average speed formula is
average speed = ...............1
put here value
average speed =
average speed is 0.159 m/s
and
average velocity formula is
average velocity = ...............2
here displacement is initial point to final point and here is 0.0463 m
put here value
average velocity =
average velocity = 0.0011 m/s
Answer:
A
Explanation:
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