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san4es73 [151]
3 years ago
8

A moving small car has a head-on collision with a large stationary truck 7.3 times the mass of the car. Which statement is true

about the direction of the car after the collision if the collision is elastic? The car continues moving in its initial direction with the same velocity. The car bounces off and moves in the opposite direction. The car keeps moving in its initial direction with a lower velocity than at first. The car stops completely.
Physics
2 answers:
ad-work [718]3 years ago
8 0
The car bounces off and moves in the opposite direction
UkoKoshka [18]3 years ago
4 0
The car bounces off and moves in the opposite direction 
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Answer:

B.

Explanation:

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It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar had a constant accelerati
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A man-made satellite orbits the earth in a circular orbit that has a radius of 32000 km. The mass of the Earth is 5.97e 24 kg. W
Gwar [14]

Answer:

= 3521m/s

The tangential speed is approximately 3500 m/s.

Explanation:

F = m * v² ÷ r

Fg = (G * M * m) ÷ r²

(m v²) / r = (G * M * m) / r²

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v = √( G * M ÷ r)

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v = √1.24 * 10⁷  

v = 3521.36m/s

The tangential speed is approximately 3500 m/s.

8 0
3 years ago
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How does the voltage applied to the electric motor affect the coil's number of rotations and its rotational direction
sleet_krkn [62]
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3 0
3 years ago
A particle with a charge of 5.13 μC has a velocity of 8.64 x106 m/s in a direction perpendicular to a magnetic fieldof 1.99 x 10
Svetach [21]

Answer:

F= 0.009 N

Explanation:

Given that

Charge ,q= 5.13 μC

Velocity ,V= 8.64 x 10⁶ m/s

Magnetic field , B = 1.99 x 10⁻⁴ T

The force on a charge q moving with velocity v is given as follows

F= q V B

Now by putting the values in the above equation we get

[tex]F= 5.13\times 10^{-6}\times 8.64\times 10^{6}\times 1.99\times 10^{-4}\ N [\tex]

F=0.00882 N

F= 0.009 N

Therefore the force on the particle will be 0.009 N.

5 0
3 years ago
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