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san4es73 [151]
2 years ago
8

A moving small car has a head-on collision with a large stationary truck 7.3 times the mass of the car. Which statement is true

about the direction of the car after the collision if the collision is elastic? The car continues moving in its initial direction with the same velocity. The car bounces off and moves in the opposite direction. The car keeps moving in its initial direction with a lower velocity than at first. The car stops completely.
Physics
2 answers:
ad-work [718]2 years ago
8 0
The car bounces off and moves in the opposite direction
UkoKoshka [18]2 years ago
4 0
The car bounces off and moves in the opposite direction 
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A 500-Ω resistor, an uncharged 1.50-μF capacitor, and a 6.16-V emf are connected in series. (a) What is the initial current? (b)
Alexeev081 [22]

Answer:

a) 0.01232 A

b) 0.00075 s = 0.75 ms

c) 0.0045323 A = 4.532 mA

d) 3.894 V

Explanation:

R = 500 Ω

V = 6.16 V

C = 1.50 μF

Let Vs be the voltage of the emf source

Let Vc be the voltage across the capacitor at any time

a) Current flows as a result of potential difference between two points. So, the current flows according to difference in voltage between the emf source and the capacitor.

At time t = 0,

There is no voltage on the capacitor; Vc = 0 V

Current in the circuit is given by

I = (Vs - Vc)/R

I = (6.16 - 0)/500

I = 0.01232 A

b) Time constant for an RC circuit is given by τ

τ = RC = (500) (1.5 × 10⁻⁶) = 0.00075 s

c) The current decay in an RC circuit (called decay because the current in the circuit starts to fall as the capacitor's voltage rises as the capacitor charges) is given by

I = I₀ e⁻ᵏᵗ

where k = (1/τ)

I₀ = Current in the circuit at t = 0 s; I₀ = 0.01232 A

At t = τ = 0.00075 s, kt = (τ/τ) = 1

I = 0.01232 e⁻¹ = 0.0045323 A = 4.532 mA

d) The voltage for a charging capacitor is given by

Vc = Vs (1 - e⁻ᵏᵗ)

where k = (1/τ)

At t = τ = 0.00075 s, Vc = ?, Vs = 6.16 V, kt = 1

Vc = 6.16 (1 - e⁻¹) = 6.16 (0.6321)

Vc = 3.894 V

4 0
3 years ago
Read 2 more answers
If you lived on the Moon, would you see Earth go through phases? If so, would the sequence of phases be the same as those of the
marissa [1.9K]

Answer:

yes; yes

Explanation:

Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.

When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.

8 0
2 years ago
Mary is allergic to cats. Mary's friend, Sue, has a roommate who has cats. Whenever Mary visits Sue, Mary sneezes even before sh
ValentinkaMS [17]

Answer: Extinction

Explanation: Extinction simply means cessation. A condition whereby an action or behavior exhibited by an individual or organism eventually stops. In psychological parlance, extinction is usually attributed to the discontinuance of a certain behavior usually due to non - reinforcement or eventual absence of the conditioned stimulus.

In the scenario above, the point at which Mary stopped sneezing is called extinction which is due to the removal of the cat which is the cause of Mary's sneezing behavior.

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2 years ago
In a grandfather clock, the second hand moves forward by one second for each half period of the clock’s pendulum.
Maurinko [17]

To solve the problem it is necessary to take into account the concepts related to simple pendulum, i.e., a point mass that is suspended from a weightless string. Such a pendulum moves in a harmonic motion -the oscillations repeat regularly, and kineticenergy is transformed into potntial energy and vice versa.

In the given problem half of the period is equivalent to 1 second so the pendulum period is,

T= 2s

From the equations describing the period of a simple pendulum you have to

T = 2\pi \sqrt{\frac{L}{g}}

Where

g= gravity

L = Length

T = Period

Re-arrange to find L we have

L = \frac{gT^2}{4\pi^2}

Replacing the values,

L = \frac{(9.8)(2)^2}{4\pi^2}

L = 0.99m

In the case of the reduction of gravity because the pendulum is in another celestial body, as the moon for example would happen that,

T = 2\pi \sqrt{\frac{L}{g/6}}

T = 2\pi\sqrt{\frac{6L}{g}}

T = 2\pi \sqrt{\frac{6*0.99}{9.8}}

T  = 4.89s

In this way preserving the same length of the rope but decreasing the gravity the Period would increase considerably.

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3 years ago
Intellectual health is
Aleks [24]

Answer:

activities that stimulate the mind

Intellectual health refers to activities that stimulate the mind and includes many forms of personal expression. Aspects of intellectual health include learning and using life skills such as critical thinking, decision-making, organization, and problem-solving.

Explanation:

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2 years ago
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