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aivan3 [116]
3 years ago
12

Two ideal gases have the same mass density and the same absolute pressure. One of the gases is helium (He), and its temperature

is 175 K The other gas is neon (Ne). What is the temperature of the neon?
Physics
1 answer:
Oxana [17]3 years ago
4 0

Answer:

Temperature of neon gas = 875 K

Explanation:

Using Ideal gas equation as:

PV=nRT

Where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the temperature

Also,

moles=\frac{Mass(m)}{Molar\ mass (M)}

Density (\rho)=\frac{Mass(m)}{Volume(V)}

The ideal gas equation can be written as:

P=\frac{Mass(m)}{Molar\ mass (M)\times Volume(V)}\times RT

Thus,

P=\frac{Density (\rho)}{Molar\ mass (M)}\times RT

P\times M=Density (\rho)\times RT

As Density and Pressure is constant , We only consider molar mass and Temperature which are directly proportional according to the equation above as:

\frac {M_1}{T_1}=\frac {M_2}{T_2}

Data given for He:

Temperature (T₁) = 175 K

Molar mass of He (M₁)= 4 g/mol

For Ne:

Temperature (T₂)= ?

Molar mass of He (M₂)= 20 g/mol

Applying in the equation,

T_2=\frac {M_2}{T_1} \times {M_1}

T_2=\frac {20 g{mol}^{-1}}{175 K} \times {4 g{mol}^{-1}}

T_2=875 K atm

<u>Temperature of neon gas = 875 K</u>

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White light is an _____________ mixture of all the colors.<br> a) observable b) unequal c) equal
Musya8 [376]

Answer:

unequal

Explanation:

White light is a combination of all colors in the color spectrum.

6 0
3 years ago
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When a wave moves from one medium to another, which properties of the wave change? choose all that apply.
Furkat [3]

In most cases, when wave refract, frequency and amplitude will be constant while wavelength and speed will change.

<h3>PROPERTIES OF WAVES</h3>

The four properties of waves are:

  • Frequency
  • Amplitude
  • Wavelength
  • Speed

When a wave moves from one medium to another, the wave will undergo refraction.

When a wave move for instance, from water to glass, the wave will refract by changing direction. In most scenario, the frequency of the wave will be constant while the wavelength of the wave will change. Since the wavelength will change, the speed will also change.

Therefore, when a wave moves from one medium to another, the properties of the wave that change are wavelength and wave speed.

Learn more about Wave here: brainly.com/question/12215474

8 0
2 years ago
"If E = 7.50V and r=0.45Ω, find the minimum value of the voltmeter resistance RV for which the voltmeter reading is within 1.0%
Virty [35]

Answer:

The  minimum value is R_V =44.552\  \Omega

Explanation:

From the question we are given that

                  The voltage is E = 7.5V

                  The internal  resistance is r = 0.45

The objective of this solution is to obtain the minimum value of the voltmeter resistance for which the voltmeter reading is within 1.0% of the emf of the battery

  What is means is that we need to obtain voltmeter resistance such that

                                V = (100% -1%) of E

Where E  is the  e.m.f of the battery and V is the voltmeter reading

                          i.e    V = 99% of E = 0.99 E = 7.425  

Generally

                E = V + ir

     where ir is the internal potential difference of the voltmeter and

                V is the voltmeter reading

 Making i the subject of the formula above

            i = \frac{(E-V)}{r}

               =\frac{7.50-7.425}{0.45}

              = 0.1667 A

Now the current is constant through out the circuit so,

                  V = iR_V

Where  R_V is the value of voltmeter resistance

                Hence R_V = \frac{V}{i}  = \frac{7.425}{0.1667}

                                  =44.552\  \Omega

                       

8 0
3 years ago
A syringe containing 1.55 ml of oxygen gas is cooled from 95.3 °c to 0.0 °c. what is the final volume of oxygen gas?\
irinina [24]
Consider the gas to be an ideal gas (it will obey all the introductory gas laws). Also you have to note that the gas will not change phase. It won't.

T_s (Temperature Start) = 95.3o C = 95.3 + 273 = 368.3 oK (degrees Kelvin)
T_e (Temperature End) = 0o C + 273 = 273 oK

Initial volume = Vi = 1.55 mL (no need to change to Liters. The answer will be in mL

 Vi /Ts =  Ve / Vs Ve is the unknown volume that you seek.
1.55 / 368.3  =  Ve / 273
Ve = 1.55 * 273 / 368.3
Ve = 1.1489 mL

If your teacher is concerned about Sig digs, then 0.0 has only two.
Your answer should be 1.1 mL, but I'll give you the choice.



3 0
4 years ago
A tall cylinder with a cross-sectional area 12.0 cm² is partially filled with mercury; the surface of the mercury is 5.00 cm abo
JulijaS [17]

Answer:

V = 816 cm^3

Explanation:

As we know that gauge pressure of the fluid at the bottom of the cylinder is given as

P = \rho g h

now we know that pressure at the bottom is double when water is poured on the mercury

So we have

\rho_{hg} g h_1 = \rho_w g h_2

so we will have

13.6 \times 5 = 1 \times h

so we have

h = 68 cm

now the volume of the water added to it is given as

V = h A

V = (68 cm)(12 cm^2)

V = 816 cm^3

6 0
4 years ago
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