Using the constant acceleration formula v^2 = u^2 + 2as, we can figure out that it would take a distance of 193.21m to reach 27.8m/s
To solve this problem we will apply the geometric concepts of displacement according to the description given. Taking into account that there is an initial displacement towards the North and then towards the west, therefore the speed would be:


Travel north 2mph and west to 1mph, then,


The route is done exactly the same to the south and east, so make this route twice, from the definition of speed we have to




Therefore the total travel time for the man is 1.15hour.
Answer:
When the ball goes to first base it will be 4.23 m high.
Explanation:
Horizontal velocity = 30 cos17.3 = 28.64 m/s
Horizontal displacement = 40.5 m
Time
Time to reach the goal posts 40.5 m away = 1.41 seconds
Vertical velocity = 30 sin17.3 = 8.92 m/s
Time to reach the goal posts 40.5 m away = 1.41 seconds
Acceleration = -9.81m/s²
Substituting in s = ut + 0.5at²
s = 8.92 x 1.41 - 0.5 x 9.81 x 1.41²= 2.83 m
Height of throw = 1.4 m
Height traveled by ball = 2.83 m
Total height = 2.83 + 1.4 = 4.23 m
When the ball goes to first base it will be 4.23 m high.
Swimmer and Divers. The Potential energy is transferred into Kinetic energy, and allows the diver to submerge into the water. The Kinetic energy then allows the diver to submerge and dive into the water. Potential energy however, is needed to allow the diver to get back out of the water after diving to get up and go and dive again, and then the Kinetic energy is transferred back to Potential energy to repeat the process.
Hope :) -Emilie Xo this is right and it helps! Xo
Answer:

at t = 0.001 we have

at t = 0.01

at t = infinity

Explanation:
As we know that they are in series so the voltage across all three will be sum of all individual voltages
so it is given as

now we will have

now we have

So we will have

at t = 0 we have
q = 0

also we know that
at t = 0 i = 0




so we have

at t = 0.001 we have

at t = 0.01

at t = infinity
