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ser-zykov [4K]
3 years ago
14

Which methods could you use to calculate the y-coordinate of the midpoint of a vertical line segment with endpoints at (0, 0) an

d (0, 15)?
Chemistry
2 answers:
maria [59]3 years ago
8 0

One of the most convenient ways of finding or calculating for the midpoint of the line segment is to get the average of the coordinates of the points.

Average of abscissa = (0 + 0) / 2 = 0

Average of ordinate = (0 + 15) / 2 = 7.5

 Hence, the midpoint of the line segment is equal to (0, 15/2).

The value of the y-intercept is 15/2. 

GREYUIT [131]3 years ago
6 0

Answer : The y-coordinate of the midpoint of a vertical line segment is, 7.5

Step by step explanation :

The method used to calculate the y-coordinate of the midpoint of a vertical line segment is, Mid-point formula.

If a line segment AB with endpoints at (x_A,x_B) and (y_A,y_B)

The mid-point formula will be,

M=(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2})

Now we have to calculate the x-coordinates and y-coordinates.

The given endpoints are, (0, 0) and (0, 15)

x_A=0,x_B=0\\\\y_A=0,y_B=15

M=(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2})

M=(\frac{0+0}{2},\frac{0+15}{2})=(0,7.5)

The x-coordinate of the midpoint of a vertical line segment is, 0

The y-coordinate of the midpoint of a vertical line segment is, 7.5

Therefore, the y-coordinate of the midpoint of a vertical line segment is, 7.5

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<u>Answer:</u> The moles of CO_2 added to the system is 7.13 moles

<u>Explanation:</u>

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K_c=\frac{(\frac{2.40}{4.00})\times (\frac{2.40}{4.00})}{(\frac{1.00}{4.00})\times (\frac{1.00}{4.00})}\\\\K_c=5.76

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\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

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