A car going initially with a velocity 13.5 m/s accelerates at a rate of 1.9 m/s for 6.2 s. It then accelerates at a rate of-1.2
2 answers:
Answer:
a) Maximum speed = 25.28 m/s
b) Total time = 27.26 s
c) Total distance traveled = 390,5537
Explanation:
In order to solve the first proble we just have to use the next formula:
So the maximum speed would be 25,28 m/s.
THe total time of the trip will be given by adding the inital time plus the velocity divided by the acceleration rate:
Remember that when dealing with time in physics you will always use positive numbers since there is no negative time.
To calculate the total distance covered we use the next formula:
This is the first part now we calculate it with the stopping of the car:
No we just add the two distances to discover the whole distance:
Total distance= 124,268+266,2857= 390,5537
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To develop this problem it will be necessary to apply the concepts related to the frequency of a spring mass system, for which it is necessary that its mathematical function is described as
Here,
k = Spring constant
m = Mass
Our values are given as,
Rearranging to find the spring constant we have that,
Therefore the spring constant is 1.38N/m
Answer:
Explanation:
A mass of 700 kg will exert a force of
700 x 9.8
= 6860 N.
Amount of compression x = 4 cm
= 4 x 10⁻² m
Force constant K = force of compression / compression
= 6860 / 4 x 10⁻²
= 1715 x 10² Nm⁻¹.
Let us take compression of r at any moment
Restoring force by spring
= k r
Force required to compress = kr
Let it is compressed by small length dr during which force will remain constant.
Work done
dW = Force x displacement
= -kr -dr
= kr dr
Work done to compress by length d
for it r ranges from 0 to -d
Integrating on both sides
W =
= [ kr²/2]₀^-4
= 1/2 kX16X10⁻⁴
= .5 x 1715 x 10² x 16 x 10⁻⁴
= 137.20 J