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Law Incorporation [45]
4 years ago
8

Calculate the volume of this regular solid.

Physics
1 answer:
My name is Ann [436]4 years ago
3 0

Answer:

2144.66 cm³

Explanation:

the formula is

V= 4 /3πr³

  = 4/3 × π × 8³

 = 4/3 × π × 512

  = 2144.66 cm³

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17,874,000 what is the value of 1
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When 0.1375 g of solid magnesium is burned in a constant-volume bomb calorimeter, the temperature increases by 1.126°C. The heat
Bumek [7]

Answer:

-24.76 kJ/mol

Explanation:

given,

mass of solid magnesium burned = 0.1375 g

the temperature increases by(ΔT) 1.126°C

heat capacity of of bomb calorimeter (C_{cal})= 3024 J/°C

heat absorbed by the calorimeter

    q_{cal} = C_{cal}\DeltaT

    q_{cal} = 3024 \times 1.126

    q_{cal} =3405.24\ J

    q_{cal} =3.405\ kJ

heat released by the reaction

    q_{rxn} = -q_{cal}

    q_{rxn} = -3.405\ kJ

energy density will be equal to heat released by the reaction divided by the mass of magnesium

Energy density = \dfrac{-3.405}{0.1375}

Energy density = -24.76 kJ/mol

heat given off by burning magnesium is equal to -24.76 kJ/mol

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3 years ago
What is one example of the use of rolling kinetic friction?
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Railroad steel wheels. Bowling ball.
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