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3 years ago

Factor the following binomial: 14a^4b^3c + 18a^2b

Mathematics

1 answer:

Alla [95]3 years ago

8 0

Answer:

2 a^2 b (7 a^2 b^2 c + 9)

Step-by-step explanation:

Factor the following:

14 a^4 b^3 c + 18 a^2 b

Hint: | Factor common terms out of 14 a^4 b^3 c + 18 a^2 b.

Factor 2 a^2 b out of 14 a^4 b^3 c + 18 a^2 b:

Answer: 2 a^2 b (7 a^2 b^2 c + 9)

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Step-by-step explanation:

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3 years ago

Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in

Luda [366]

ANSWER: 32 five-dollar bills

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EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

$\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.$

Divide both sides of equation (II) by 5 so our numbers become smaller

$\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.$

Rearrange (I) to solve for y so that we can substitute into (II)

$\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}$

Substituting this into equation (II) for the y:

$\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}$

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======

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3 years ago

Prove the following using a direct proof:

hodyreva [135]

Answer:

Step-by-step explanation:

Prove: That the sum of the squares of 4 consecutive integers is an even integer.

An integer is a any directed number that has no decimal part or indivisible fractional part. Examples are: 4, 100, 0, -20,-100 etc.

Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;

$5^{2}$ = 25

$6^{2}$ = 36

$7^{2}$ = 49

$8^{2}$ = 64

The sum of the squares = 25 + 36 + 49 + 64

= 174

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Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;

$-10^{2}$ = 100

$-11^{2}$ = 121

$-12^{2}$ = 144

$-13^{2}$ = 169

The sum of the squares = 100 + 121 + 144 + 169

= 534

Therefore, the sum of the squares of 4 consecutive integers is an even integer.

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