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3 years ago

What is the resultant velocity of a plane that is traveled at 245m/s, north and encounters a tailwind of 55m/s?

Physics

1 answer:

lesya [120]3 years ago

6 0

For this problem, you should use Pythagorean Theorem.

The formula for this is a^2 + b^2 = c^2.

The plane is moving north, and then moves to the right. Therefore, we need to find the hypotenuse, or resultant velocity. Plugging it into the equation we get, (245 m/s)^2 + (55 m/s)^2 = c^2

Solving for this, you will get 250 m/s.

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Agata [3.3K]

Answer:

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Explanation:

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iVinArrow [24]

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3 years ago

Your grandmother enjoys creating pottery as a hobby. She uses a potter's wheel, which is a stone disk of radius R-0.520 m and ma

Lesechka [4]

Answer:

0.54454

104.00902 N

Explanation:

m = Mass of wheel = 100 kg

r = Radius = 0.52 m

t = Time taken = 6 seconds

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

Mass of inertia is given by

$I=\dfrac{mr^2}{2}\\\Rightarrow I=\dfrac{100\times 0.52^2}{2}\\\Rightarrow I=13.52\ kgm^2$

Angular acceleration is given by

$\alpha=\dfrac{\tau}{I}\\\Rightarrow \alpha=\dfrac{\mu fr}{I}\\\Rightarrow \alpha=\dfrac{\mu 50\times 0.52}{13.52}$

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=\omega_i+\dfrac{\mu (-50)\times 0.52}{13.52}t\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{\mu (-50)\times 0.52}{13.52}\times 6\\\Rightarrow 0=6.28318-11.53846\mu\\\Rightarrow \mu=\dfrac{6.28318}{11.53846}\\\Rightarrow \mu=0.54454$

The coefficient of friction is 0.54454

At r = 0.25 m

$\omega_f=\omega_i+\dfrac{0.54454 (-50)\times 0.52}{13.52}6\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{0.54454 f\times 0.25}{13.52}6\\\Rightarrow 2\pi=0.06041f\\\Rightarrow f=\dfrac{2\pi}{0.06041}\\\Rightarrow f=104.00902\ N$

The force needed to stop the wheel is 104.00902 N

5 0

3 years ago

Help

Mama L [17]

<h3><u>Answer;</u></h3>

producing a path for current to flow

<h3><u>Explanation;</u></h3>

An AC generator is a device that converts mechanical energy into electrical energy using the principle of electromagnetic induction.
<em><u>Slip rings are two hollow rings to which two ends of the armature coil are connected. These rings rotate with the rotation of the coil. They function to to allow for electrical contact with the brushes.</u></em>
Slip rings therefore, provide a means for connecting the rotating armature to an external circuit.

3 0

3 years ago

Read 2 more answers

Correct me if im wrong

White raven [17]

Your answer is correct. No problem and Have a nice day

6 0

3 years ago