Energy is the ability to do work. All of the following describe work being done EXCEPT:

Two objects, A and B, each of mass o.22 kg, are moving at 0.34 m/s directly toward each other. What is the speed of Object A aft

ki77a [65]

Theoretically, if the objects have the same mass and are moving towards each other at a speed of $0.34m s^{-1}$ , after a perfectly elastic collision, the object A is supposed to move with the same velocity in the opposite direction.

6 0

3 years ago

To model time-variant data, one must create a new entity in an m:n relationship with the original entity.

Ksenya-84 [330]

To model time-variant data, one must create a new entity in an m:n relationship with the original entity, is a False statement.

Like the majority of software engineering initiatives, the ER process begins with gathering user requirements. What information must be retained, what questions must be answered, and what business rules must be implemented (For instance, if the manager column in the DEPARTMENT table is the only column, we have simply committed to having one manager for each department.)

The end result of the E-R modeling procedure is an E-R diagram that can be roughly mechanically transformed into a set of tables. Tables will represent both entities and relationships; entity tables frequently have a single primary key, but the primary key for relationship tables nearly invariably involves numerous characteristics.

To know more about entity AND relationship visit : brainly.com/question/28232864

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6 0

1 year ago

Image caught on Screen is called

bixtya [17]

Answer:

<h2>Virtual image</h2>

Explanation:

<h3>Virtual image can be caught on a screen</h3>

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4 0

3 years ago

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A spherical soap bubble with a surface-tension of 0.005 lbf/ft is expanded from a diameter of 0.5 in to 3.0 in. How much work, i

Sladkaya [172]

Answer:W = 1.23×10^-6BTU

Explanation: Work = Surface tension × (A1 - A2)

W= Surface tension × 3.142 ×(D1^2 - D2^2)

Where A1= Initial surface area

A2= final surface area

Given:

D1=0.5 inches , D2= 3 inches

D1= 0.5 × (1ft/12inches)

D1= 0.0417 ft

D2= 3 ×(1ft/12inches)

D2= 0.25ft

Surface tension = 0.005lb ft^-1

W = [(0.25)^2 - (0.0417)^2]

W = 954 ×10^6lbf ft × ( 1BTU/778lbf ft)

W = 1.23×10^-6BTU

8 0

3 years ago

Problems - Show all work.

Fittoniya [83]

Answer:

21s

Explanation:

Given parameters;

Radius = 10m

Speed or velocity = 3m/s

Unknown:

Period = ?

Solution:

To solve this problem, use the expression:

v = $\frac{2\pi r}{T}$

r is the radius

T is the unknown

Input the parameters and solve for T;

3 = $\frac{2 x \pi x 10}{T}$

62.84 = 3T

T = 21s

4 0

3 years ago