What was the major shortcoming of rutherford’s model of the atom?
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F=nmv
where;
n=no. of bullets = 1
m=mass of bullets=2g *10^-3
V=velocity of bullets200m/sec
F=1
loss in Kinetic energy=gain in heat energy
1/2MV^2=MS∆t
let M council M
=1/2V^2=S∆t
M=2g
K.E=MV^2/2
=(2*10^-3)(200)^2/2
2 councils 2
2*10^-3*4*10/2
K.E=40Js
H=mv∆t
(40/4.2)
40Js=40/4.2=mc∆t
40/4.2=2*0.03*∆t
=158.73°C
Answer : 2446 years.
Explanation :
Length of semi major axis is,
According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.
i.e
where G is gravitational constant
M is mass of sun,
So,
since,
So, orbital period is approximately 2446 years.