<span>There is an low cost and quickest alternative available for adaptive optics. Name of this technique is wavefront coding. The numerical analysis pretends to show the robustness of the technique under changes in pupil diameter and wavefront shape including intersubject and intrasubject variability, using always the same restoration filter or image decoder .Using this technique it is possible to obtain high resolution images under different ocular aberrations and pupil diameters with the same decoder, opening the possibility of real time high resolution images.</span>
Answer:
Momentum is the product of a moving object's mass and velocity . ... When two objects collide the total momentum before the collision is equal to the total momentum after the collision (in the absence of external forces). This is the law of conservation of momentum. It is true for all collisions.
Explanation:
Answer:
Random errorrs
1) Variations in the level of the eye when we measure the dimensions of the cubic piece using the metric rule.
2) Possible vibrations or disbalance when we measure the mass of the of the cylinder.
Systematic errors
3) Wrong calibration for the balance and that represent a measurement wrong
Explanation:
Previous concepts
Random error represent an statistical error associated to the effect random in the experiment.
Systematic error is a "repeatable error associated with faulty equipment or a flawed experiment design", so is an error non controlled.
Solution to the problem
So as we can see we have two possible types of errors : random and systematic errors. For this stuation the list of 3 errors required are:
Random errors
1) Variations in the level of the eye when we measure the dimensions of the cubic piece using the metric rule.
2) Possible vibrations or disbalance when we measure the mass of the of the cylinder.
Systematic errors
3) Wrong calibration for the balance and that represent a measurement wrong
Answer:
102597.6 Pa
Explanation:
mass, m = 1.25 g
Force, F = m x g = 1.25 x 9.8 x 10^-3 = 0.01225 N
radius, r = 0.195 mm = 0.195 x 10^-3 m
Area, A = πr² = 3.14 x 0.195 x 0.195 x 10^-6 m^2
A = 1.19 x 10^-7 m^2
Pressure is defined as the thrust acting per unit area.
P = Force / Area
P = 0.01225 N / (1.10 x 10^-7)
P = 102597.6 Pa
Thus, the pressure exerted is 102597.6 Pa.
A daffodil is actually a producer
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