Answer:
carbon dioxide
Explanation:
Carbon burns in oxygen to form carbon dioxide. Since hydrocarbon fuels only contain two elements, we always obtain the same two products when they burn. In the equation below methane (CH 4) is being burned. The oxygen will combine with the carbon and the hydrogen in the methane molecule to produce carbon dioxide (CO 2) and water (H 2O).
Carbon, as graphite, burns to form gaseous carbon (IV) oxide (carbon dioxide), CO2. ... When the air or oxygen supply is restricted, incomplete combustion to carbon monoxide, CO, occurs. 2C(s) + O2(g) → 2CO(g) This reaction is important. When one mole of carbon is exposed to some energy in the presence of one mole of oxygen gas, one mole of carbon dioxide gas is produced. This reaction is a combustion reaction.
I think that the answer is 0.49
The range is negative numbers.
The interval for the range is .
***You might want to look at your functions again because I don't see a choice that matches.
Step-by-step explanation:
Given functions:
We are asked to find the range of .
I'm also going to look at the domain just to see if this possibly might change my range .
is the inner function. So we will consider the domain of that function first.
You only have to worry about division by zero for the function .
Since we are dividing by , we don't want to be zero.
So far the domain is all real numbers except .
Now let's move out.
exists for all numbers, . So we didn't want to include from before.
Now let's put it together:
So the domain is still all real numbers except at since we cannot divide by 0 and is 0 when .
with .
is positive for all numbers except .
So is negative for all numbers since negative divided by positive is negative.
So the range is only negative numbers.
Let's also look at the inverse:
Multiply both sides by :
Divide both sides by :
Take the square root of both sides:
.
So can't be 0 and it also can't be positive because the inside of the square root will be negative (since negative divided by positive results in negative).
Answer:
Explanation:
i would say not d im not fully sure but id say c
Answer:
The answer to your question is C = 0.037 cal/g°C
Explanation:
Data
mass of the wire = m = 237 g
temperature 1 = T1 = 25°C
temperature 2 = T2 = 107°C
Heat = Q = 722 cal
Specific heat = C
Process
1.- Write the formula to find the specific heat
Q = mC(T2 - T1)
-Solve for C
C = Q / m(T2 - T1)
2.- Substitution
C = 722 / 237(107 - 25)
3.- Simplification
C = 722 / 237(82)
C = 722 / 19434
4.- Result
C = 0.037 cal/g°C
