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avanturin [10]
3 years ago
10

Can 50g of NaCl dissolve in 100 g of water at 60 C?*

Chemistry
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

Explanation:

The solubility of sodium chloride at 60 degree in water is 37.04 gm / 100 mL

or 37.04 gm / 100 gm of water

So 50g of NaCl can not be dissolved in 100 g of water.

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HELP PLASE I NEED A's AND B's PLEASE
lilavasa [31]

Answer:

I'm guessing where it is located in the earth for example if a part of a biome is closer to the equator it will be more warm and tropical the further from the equator it will be colder and less tropical.

Explanation:

3 0
3 years ago
4. Does an atom of an element always have the same number of neutrons as other atoms of the same
Sergeeva-Olga [200]

Explanation:

No. Isotopes are atoms of the same element with different atomic masses (due to the different number of neutrons)

For example, carbon exists as carbon-12 and carbon-14, which both have 6 protons but have 6 and 8 neutrons respectively.

6 0
3 years ago
Balance the following equation.<br> C3H8(g) + O2(g) → CO2(g) + H2O(l)
Arte-miy333 [17]

Explanation:

C3H8+5O2----->3CO2+4H2O

8 0
3 years ago
A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t
pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = pK_a=9.31

First we have to calculate the moles of HCN and NaCN.

\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole

and,

\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole

The balanced chemical reaction is:

                          HCN+NaOH\rightarrow NaCN+H_2O

Initial moles     0.1116       0.0461     0.08978

At eqm.       (0.1116-0.0461)    0       (0.08978+0.0461)

                        0.0655                       0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=9.31+\log (\frac{0.1359}{0.0655})

pH=9.63

Therefore, the pH of the solution is, 9.63

4 0
3 years ago
A student needs exactly 1 gram of baking powder to conduct an experiment. The balance reads 0.37 grams. How
sammy [17]

Answer:

B

Explanation:

If the student needs one gram but so far only has 0.37 grams, then the amount they need is the difference between what they need and how much they already have. 1-0.37=0.63 grams.

...which isn't actually an option because none of them have decimal points but I would say it is B anyway because it is the equivalent ratio and maybe there was a typo.

Hope this helped!

6 0
3 years ago
Read 2 more answers
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