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3 years ago

Bats use ultrasound in echolocation. This sound is characterized by _____.

Physics

2 answers:

Gnoma [55]3 years ago

8 0

Answer:

<u>C. high frequency </u>

Explanation:

Bats use high frequency sound waves -ultra sound (20 to 200 kHz) to locate their prey via a technique -echolocation. The produce these sound waves and when the waves reflect from a prey nearby, they are able to estimate the size, position and speed of their prey. The human hearing range is up to 20 kHz, so we can hear the sound produced by some of the bats.

Elanso [62]3 years ago

4 0

High frequency, as humans cannot hear the sound of the bats using echolocation because of it's such high frequency.
Hope this helps :)

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what causes places near the equator to receive more direct sunlight than the poles? the poles are farther away from the sun than

Andru [333]

This is due to the tilt of the earth on its axis. Although the Sun shines on Earth, because of how the Earth is tilted, the equator is more directly hit compared to places found on the poles. The poles are hit at an angle, therefore the sunlight they receive is lesser than the places at the equator.

5 0

2 years ago

A biologist looking through a microscope sees a bacterium at r⃗ 1=2.2i^+3.7j^−1.2k^μm(1μm=10−6m). After 6.2 s , it's at r⃗ 2=4.6

stiv31 [10]

The Average velocity for the bacterium is 0.75 unit/sec.

<u>Explanation:</u>

The given values are in the vector form

Where,

dS = distance covered

dT = time interval

Now, to calculate distance covered, we have

$|d S|=\sqrt{d S^{2}}$

$d S=r_{2}-r_{1}$

d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)

d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k

d S=2.4 i-3.7 j+3.1 k

Now, putting these values in the standard formula to evaluate the average velocity, we get;

$v_{a v g}=\frac{|\mathrm{d} S|}{d T}$

$v(a v g)=\frac{|\sqrt{\left\{\left(2.4^{2}\right)+\left(3.7^{2}\right)+\left(3.1^{2}\right)\right\}}|}{7.2}$

As dT=7.2 sec

Now,

Solving the equation, we get;

$v(a v g)=\frac{5.390732789}{7.2}$

$\begin{aligned}&v(a v g)=\frac{5.39}{7.2}\\&v(a v g)=0.748611111\\&v(a v g)=0.75 \text { units / sec }\end{aligned}$

Hence, the average velocity for the bacterium is 0.75 unit/sec.

3 0

3 years ago

Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen

Marta_Voda [28]

Answer:

a) that laser 1 has the first interference closer to the central maximum

c) Δy = 0.64 m

Explanation:

The interference phenomenon is described by the expression

d sin θ = m λ

Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference

For the separation of the lines we use trigonometry

tan θ = sin θ / cos θ = y / x

In interference experiments the angle is very small

tan θ = sin θ = y / x

d y / x = m λ

a) and b) We apply the equation to the first laser

λ = d / 20

d y / x = m d / 20

y = m x / 20

y = 1 4.80 / 20

y = 0.24 m

The second laser

λ = d / 15

d y / x = m d / 15

y = m x / 15

y = 0.32 m

We can see that laser 1 has the first interference closer to the central maximum

c) laser 1

They ask us for the second maximum m = 2

y₂ = 2 4.8 / 20

y₂ = 0.48 m

For laser 2 they ask us for the third minimum m = 3

In this case to have a minimum we must add half wavelength

y₃ = (m + ½) x / 15

m = 3

y₃ = (3 + ½) 4.8 / 15

y₃ = 1.12 m

Δy = 1.12 - 0.48

Δy = 0.64 m

4 0

2 years ago

A3 kg mass takes some impulse in order increase its velocity from 11

Butoxors [25]

Answer:

JAKSJAKZNPWLAQJZOAKZONZPW

THE ANSWER IS FAILURE

4 0

3 years ago

Which resultant force is NOT possible if 50 N force and a 60 N force act concurrently?

Sergio [31]

Answer:

The options are not shown, so i will answer in a general way.

Suppose the case where the forces act in opposite directions, then we need to subtract the forces, and we know that the magnitude of the resultant force will be:

60N - 50N = 10N

Now, suppose the case where both forces act in the exact same direction, in that case, we will add the forces to get:

60N + 50N = 110N

Then the only range of forces that we can get in this system, are the forces such:

10N ≤ F ≤ 110N

Any resultant force outside that range is not possible in this situation.

3 0

2 years ago