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kondaur [170]
4 years ago
15

Bats use ultrasound in echolocation. This sound is characterized by _____.

Physics
2 answers:
Gnoma [55]4 years ago
8 0

Answer:

<u>C. high frequency  </u>

Explanation:

Bats use high frequency sound waves -ultra sound (20 to 200 kHz) to locate their prey via a technique -echolocation. The produce these sound waves and when the waves reflect from a prey nearby, they are able to estimate the size, position and speed of their prey. The human hearing range is up to 20 kHz, so we can hear the sound produced by some of the bats.

Elanso [62]4 years ago
4 0
High frequency, as humans cannot hear the sound of the bats using echolocation because of it's such high frequency.
Hope this helps :)
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3 years ago
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What is the frequency of an electromagnetic wave that has a wavelength of 300,000 km? (the speed of light is 300,000 km/s.)?
expeople1 [14]
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The speed (m/s) of a wave is given by  frequency (Hz) × Wavelength (m)
Speed is 300,000 km/sec or 300,000,000 m/s and the wavelength is 300,000  km or 300,000,000 m.
Frequency = speed÷ wavelength
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6 0
3 years ago
What is the frequency of a wave traveling at 300,000,000 m/s with a wavelength of .0025 m/cycle ? Please explain good thank you
Reptile [31]

Answer:

The frecuency is 1.2*10¹¹ Hz.

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).

The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f * λ.

In this case:

  • v= 300,000,000 m/s
  • f= ?
  • λ= 0.0025 m

Replacing:

300,000,000 m/s= f* 0.0025 m

Solving:

f= 300,000,000 m/s ÷0.0025 m

f= 1.2*10¹¹ \frac{1}{s} =  1.2*10¹¹ Hz

<u><em>The frecuency is 1.2*10¹¹ Hz.</em></u>

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There are other examples as well, such as a battery. I decided to use the spring example because it is simpler.

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I wrote all that^.

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