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2 years ago

Give reasons :

Chemistry

2 answers:

natka813 [3]2 years ago

5 0

Answer:

Some gases are soluble in water while some are not. This is because the reactivity of different gases with water either yields no results or results in the formation of newer compounds due to this interaction.

Complete step by step answer:

Before getting to the question, let us first understand how ammonia gas is produced. For the production of ammonia, a process called upward delivery is used. In this process, gases which are lighter than air are produced. Just like hydrogen gas, ammonia gas is also lighter than air. In the setup of production of ammonia, the solid reactants are placed in a horizontal test tube and are allowed to react. This tube is connected to a collection apparatus which is placed vertically and is attached using a glass syringe.

When the solid reactants are reacting, the gases formed are collected in the collection apparatus. The lighter gases stay at the top layer of the container, while heavier gases like air are collected on the lower end and are thereby released. Hence, this process is also known as the downward displacement of air.

Elza [17]2 years ago

3 0

Ans 1:

Ammonia is not collected over water since it is highly soluble in water

Ans 2:

Ammonia gas is lighter than air and hence collected by the downward displacement of air.

Ans 3:

The carbon dioxide is very cold as it comes out of the extinguisher, so it cools the fuel as well.

Ans 4:

H₂SO₄ is not used in the preparation of carbon dioxide Because the calcium sulphate formed is insoluble in water. So, CO₂ will not form.

Ans 5:

The opening of hard glass test tube is slanted down during laboratory preparation of ammonia gas because Ammonia gas is not collected in the gas jar by upward displacement of air because it is lighter than air

Ans 6:

Magnesium is reactive enough to be combusted and oxidized in a reaction with carbon dioxide:

The magnesium strip burns brightly in the air, but continues to burn in the carbon dioxide environment

-TheUnkownScientist

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What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 11.630 g to 4.000 g ?

Dima020 [189]

The amount of sugar is 2621 mg

Why?

The complete question is:

A 12.630 g milk chocolate bar is found to contain 8.315 g of sugar.

Part B. What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 12.630 g to 4.000 g ?

To find the answer we have to determine first the amount of sugar in milligrams per gram of chocolate bar. We can find that by applying the following conversion factor:

$\frac{8.315 gSugar}{12.630 g Chocolate}*\frac{1000mg}{1g}=658.35mgSugar/gChocolate$

Now, we have to determine the amount of sugar in milligrams if we had a chocolate bar with 4.000 g:

$4.000gChocolate*\frac{658.35mgSugar}{1gChocolate}=2621mgSugar$

Have a nice day!

5 0

3 years ago

) Do you think the pH of 1,0 M tri-methyl ammonium (CH3)3NH+, pKa = 9.80, will be higher or lower than that of 1.0 M phenol, C6H

Elanso [62]

Answer:

1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).

2. The difference in pH values is 4.95.

Explanation:

1. The pH of a compound can be found using the following equation:

$pH = -log([H_{3}O^{+}])$

First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.

Trimethyl ammonium:

We can calculate [H₃O⁺] using the Ka as follows:

(CH₃)₃NH⁺ + H₂O → (CH₃)₃N + H₃O⁺

1.0 - x x x

$Ka = \frac{[(CH_{3})_{3}N][H_{3}O^{+}]}{[(CH_{3})_{3}NH^{+}]}$

$10^{-pKa} = \frac{x*x}{1.0 - x}$

$10^{-9.80}(1.0 - x) - x^{2} = 0$

By solving the above equation for x we have:

x = 0.097 = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(0.097) = 1.01$

Phenol:

C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺

1.0 - x x x

$Ka = \frac{[C_{6}H_{5}O^{-}][H_{3}O^{+}]}{[C_{6}H_{5}OH]}$

$10^{-10} = \frac{x^{2}}{1.0 - x}$

$1.0 \cdot 10^{-10}(1.0 - x) - x^{2} = 0$

Solving the above equation for x we have:

x = 9.96x10⁻⁶ = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(9.99 \cdot 10^{-6}) = 5.00$

Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.

2. The difference in pH values for the two acids is:

$\Delta pH = pH_{C_{6}H_{5}OH} - pH_{(CH_{3})_{3}NH^{+}} = 5.00 - 1.01 = 4.95$

Therefore, the difference in pH values is 4.95.

I hope it helps you!

7 0

3 years ago

When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2Al + 6HCl → 2AlCl

4vir4ik [10]

Well, we need to find the ratio of Al to the other reactant.

Al:HCl = 1:3

--> this means that for every 1 Al used, you have to use 3 HCl.

6*3 = 18 moles of HCl needed to fully react with 6 moles of Al. Since 13<18, HCL is the limiting reactant.

The ratio of HCl:AlCl = 3:1

13/3 = 4.3333...

The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced.

Hope this helps!!! :)

6 0

2 years ago

If 3.91 moles of H2 were used, how many moles of NH3 would be made? HELP PLEASE ASAP

matrenka [14]

N + H2 → NH3

balance the equation

2N + 3H2 → 2NH3

3H2 → 2NH3

3 : 2

3.91 ÷ 3 = 1.303 mol

1.3 × 2 = 2.606 mol

7 0

2 years ago

Balance the following reaction: AL2O3 + HCI ⇒ ALCI3 + H2O

Anastaziya [24]

To balance the following chemical equation, make a tally or a count of each of the atoms on both sides of the reaction, and make sure that those atoms are equal on both the reactant and product side.

AL2O3 + HCl => ALCl3 + H2O

Left side. Right side
AL = 2. AL = 1
O = 3 Cl = 3
H = 1. H = 2
Cl = 1. O = 1

First balance the metal atoms, aluminum, then hydrogen and then oxygen.

Balanced equation :
AL2O3 + 6HCl => 2ALCl3 + 3H2O.

Left side. Right side
AL = 2 AL = 2
O = 3 Cl = 6
H = 6 H = 6
Cl = 6 O = 3.

4 0

3 years ago