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ArbitrLikvidat [17]
3 years ago
15

Give reasons :

Chemistry
2 answers:
natka813 [3]3 years ago
5 0

Answer:

Some gases are soluble in water while some are not. This is because the reactivity of different gases with water either yields no results or results in the formation of newer compounds due to this interaction.

Complete step by step answer:

Before getting to the question, let us first understand how ammonia gas is produced. For the production of ammonia, a process called upward delivery is used. In this process, gases which are lighter than air are produced. Just like hydrogen gas, ammonia gas is also lighter than air. In the setup of production of ammonia, the solid reactants are placed in a horizontal test tube and are allowed to react. This tube is connected to a collection apparatus which is placed vertically and is attached using a glass syringe.

When the solid reactants are reacting, the gases formed are collected in the collection apparatus. The lighter gases stay at the top layer of the container, while heavier gases like air are collected on the lower end and are thereby released. Hence, this process is also known as the downward displacement of air.

Elza [17]3 years ago
3 0

<u>Ans 1:</u>

Ammonia is not collected over water since it is highly soluble in water

<u>Ans 2:</u>

Ammonia gas is lighter than air and hence collected by the downward displacement of air.

<u>Ans 3:</u>

The carbon dioxide is very cold as it comes out of the extinguisher, so it cools the fuel as well.

<u>Ans 4:</u>

H₂SO₄ is not used in the preparation of carbon dioxide Because the calcium sulphate formed is insoluble in water. So, CO₂ will not form.

<u>Ans 5:</u>

The opening of hard glass test tube is slanted down during laboratory preparation of ammonia gas because Ammonia gas is not collected in the gas jar by upward displacement of air because it is lighter than air

<u>Ans 6:</u>

Magnesium is reactive enough to be combusted and oxidized in a reaction with carbon dioxide:

The magnesium strip burns brightly in the air, but continues to burn in the carbon dioxide environment

<u>-</u><u>TheUnkownScientist</u>

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Answer:

8.45 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50 °C

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 0 °C

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50 °C

Initial temperature (T₁) = 50 °C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 0 °C

Final temperature (T₂) = 0 °C + 273

Final temperature (T₂) = 273 K

Finally, we shall determine the new volume. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 273 k

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

2 × 5 / 323 = 1 × V₂ / 273

10 / 323 = V₂ / 273

Cross multiply

323 × V₂ = 10 × 273

323 × V₂ = 2730

Divide both side by 323

V₂ = 2730 / 323

V₂ = 8.45 L

Thus, the new volume is 8.45 L

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